Answer:
The mass composition of ∝ ferrite is 88.94%.
The mass composition of cementite is 11.05%.
Explanation:
Given that
T=726 °C
We have to find the mass fractions of ferrite nad cementite in pearlite.
Lets take data from ideal Iron -carbon diagram at 726 °C
Composition of ∝ ferrite=0.022 5
Composition of pearlite =0.76 %
Composition of cementite =7.6%
We know that if we want to find the mass fraction the we use Lever rule .So now by using lever rule

So the mass composition of ∝ ferrite is 88.94%.

So the mass composition of cementite is 11.05%.
Answer:
(a)
Plastic section modulus Z =92.72 in^3
Plastic moment Mp = 4636 kip-in
(b)
Elastic section modulus S = 80.88 in^3
Yield moment My = 4044 kip-in
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached files.i hope my explanation will help you in understanding this particular question.
Answer:

Explanation:
The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>
The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

Thus, you can write the equations for each star:


As per Newton's third law, the centripetal forces are equal in magnitude. Then:

Now you can clear
:

Answer:
The statement (a) In a non-deterministic FSM, a string is invalid if there is one path not leading to a final state is NOT true
Explanation:
A non-deterministic FSM, contrary to deterministic FSM which has only one possible thread of execution, has multiple threads and for the machine to be invalid, all threads should lead to a none accepting (final) state.
Answer:
Your question is lacking some information attached is the missing part and the solution
A) AB = AD = BD = 0, BC = LC
AC = 
B) AB = AD = BC = BD = 0
AC = 
Explanation:
A) Forces in all members due to the load L in position A
assuming that BD goes slack from an inspection of Joint B
AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C
B) steps to arrive to the answer is attached below
AB = AD = BC = BD = 0
AC = 