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kipiarov [429]
2 years ago
7

Why would an aerospace engineer limit the maximum angle of deflection of the control surfaces?

Engineering
1 answer:
WITCHER [35]2 years ago
4 0

Answer:

You can create high drag which allows a steeper angle without increasing your air speed on landing. you can reduce the length of landing role. Flaps are also used to increase the drag they are retracted when they are not needed. it is adviseable to down he flaps during the time of take off.

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Compute the mass fractions of α ferrite and cementite in pearlite. Assume T=726⁢ C∘.
kotykmax [81]

Answer:

The mass composition of ∝ ferrite is 88.94%.

The mass composition of cementite is 11.05%.

Explanation:

Given that

T=726 °C

We have to find the mass fractions of ferrite nad cementite in pearlite.

Lets take data from ideal Iron -carbon diagram at 726 °C

Composition of ∝ ferrite=0.022 5

Composition of pearlite =0.76 %

Composition of cementite =7.6%

We know that if we want to find the mass fraction the  we use Lever rule .So now by using lever rule

The\ mass\ composition\ of\alpha \ ferrite =\dfrac{6.7-0.76}{6.7-0.022}

So the mass composition of ∝ ferrite is 88.94%.

The\ mass\ composition\ of\ cementite =\dfrac{0.76-0.022}{6.7-0.022}

So the mass composition of cementite is 11.05%.

4 0
2 years ago
A flexural member is fabricated from two flange plates 7-1/2 x ½ and a web plate 17 x 3/8. The yield stress of steel is 50 ksi.
MissTica

Answer:

(a)

Plastic section modulus Z =92.72 in^3

Plastic moment Mp = 4636 kip-in

(b)

Elastic section modulus S = 80.88 in^3

Yield moment My = 4044 kip-in

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached files.i hope my explanation will help you in understanding this particular question.

7 0
2 years ago
A binary star system consists of two stars of masses m1m1m_1 and m2m2m_2. The stars, which gravitationally attract each other, r
d1i1m1o1n [39]

Answer:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

Explanation:

The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>

The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

                a_c=\dfrac{F_c}{m}

Thus, you can write the equations for each star:

     

       a_c_1=\dfrac{F_c_1}{m_1}

       a_c_2=\dfrac{F_c_2}{m_2}

As per Newton's third law, the centripetal forces are equal in magnitude. Then:

       a_c_1\times m_1=a_c_2\times m_2

Now you can clear a_c_2:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

6 0
2 years ago
5. Which statement regarding a finite state machine (FSM) is NOT true: (a) In a non-deterministic FSM, a string is invalid if th
valkas [14]

Answer:

The statement (a) In a non-deterministic FSM, a string is invalid if there is one path not leading to a final state is NOT true

Explanation:

A non-deterministic FSM, contrary to deterministic FSM which has only one possible thread of execution, has multiple threads and for the machine to be invalid, all threads should lead to a none accepting (final) state.

7 0
2 years ago
The rectangular frame is composed of four perimeter two-force members and two cables AC and BD which are incapable of supporting
Rama09 [41]

Answer:

Your question is lacking some information attached is the missing part and the solution

A) AB = AD = BD = 0, BC = LC

    AC = \frac{5L}{3}T, CD = \frac{4L}{3} C

B) AB = AD = BC = BD = 0

   AC = \frac{5L}{3} T, CD = \frac{4L}{3} C

Explanation:

A) Forces in all members due to the load L in position A

assuming that BD goes slack from an inspection of Joint B

AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C

B) steps to arrive to the answer is attached below

AB = AD = BC = BD = 0

AC = \frac{5L}{3} T,  CD = \frac{4L}{3}C

7 0
2 years ago
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