A botanist uses the representations below to show the heights in inches, h, of different plants over a period of time, t. Plant
2 answers:
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Answer:
a) The tower is 90 feet tall
b) She reaches the bottom at t = 18 minutes.
c) Her speed at time t is 5 \sqrt[]{5} ft/minute
d) Her acceleration at time t is 10 ft/minute^2
Step-by-step explanation:
Consider the path described by the child as going down the tower to have the following parametrization
a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.
b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.
c) Given the parametrization we are given, the velocity of the child at time t is given by . The speed is defined as the norm of the velocity vector,
so, the speed at time t is given by
d) ON the same fashion we want to know the norm of the second derivative of .
We have that so the acceleration is given by
1.The isosceles triangle has sides of length 14, y, y
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.