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fredd [130]
2 years ago
8

I thought of number J, and then subtracted half of it from 34.

Mathematics
2 answers:
tangare [24]2 years ago
8 0

Answer:

34 - (J/2)

Step-by-step explanation:

Elis [28]2 years ago
3 0

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but let me help out.

You said that you thought of number J, and then subtracted half of it from 34. This can be mathematically written as:

= 34 - (J/2)

Let's reframe the question and assume that you thought of a number J, and then subtracted half of it from 34 and the answer you get is 12. To find J goes thus:

You subtract half of J from 34 and equate it to 12. This will be:

34 - (J/2) = 12

Collect like terms

34 - 12 = J/2

22 = J/2

J = 22 × 2

J = 44

In this scenario, J = 44. We can check to confirm.

Check: 34 - (J/2)

= 34 - (44/2)

= 34 - 22

= 12

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78 = 78 (correct)

so u have 2 sets of points on this line and they are (8,48) and (13,78)
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Answer:14

Step-by-step explanation:

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Billy Jo's school is selling tickets to a Fall Festival. On the first day of ticket sales the school sold 3 adult ticket and 8 s
denis23 [38]

Answer:

Y = 6

Step-by-step explanation:

On the first day of ticket sales the school <em><u>sold 3 </u></em>adult ticket and <em><u>8 student </u></em>tickets for a <em><u>total of $72</u></em>. The school took in <em><u>$152</u></em> on the second day by selling<em><u> 7 adult tickets and 16 student tickets.</u></em> How much is a student ticket?  

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This becomes a system of equations.

3x+8y=72

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7(-8/3 y + 24) + 16y = 152

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<em>If you wanted to keep going...</em>

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Hope this helps! <em>♥</em>

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6 0
2 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
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Answer:

Step-by-step explanation:

(a)

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The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

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(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

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(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

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Mila [183]

Answer:

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