answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lelechka [254]
2 years ago
11

Elena la “Exterminadora” está explorando un castillo. Un dragón la ve y la persigue por un pasillo. Elena se mete en una habitac

ión y trata de cerrar la pesada puerta antes de que el dragón la atrape. Inicialmente, la puerta es perpendicular a la pared, así que debe girar 90° para cerrarse. La puerta tiene 3.00 m de altura y 1.25 m de anchura, y pesa 750 N. Puede
despreciarse la fricción en las bisagras. Si Elena aplica una fuerza de 220 N al borde de la puerta, perpendicular a ella, ¿cuánto tardará en cerrarla?

Physics
1 answer:
Zinaida [17]2 years ago
8 0

Answer: Amazing!

Explanation:

You might be interested in
Sally finds herself stranded on a frozen pond so slippery that she can't stand up or walk on it. To save herself, she throws one
8_murik_8 [283]

Answer:

a) 2.5 m/s. (In the opposite direction to the direction in which she threw the boot).

b) The centre of mass is still at the starting point for both bodies.

c) It'll take Sally 12 s to reach the shore which is 30 m from her starting point.

Explanation:

Linear momentum is conserved.

(mass of boot) × (velocity of boot) + (mass of sally) × (velocity of Sally) = 0

5×30 + 60 × v = 0

v = (-150/60) = -2.5 m/s. (Minus inicates that motion is in the opposite direction to the direction in which she threw the boot).

b) At time t = 10 s,

Sally has travelled 25 m and the boot has travelled 300 m.

Taking the starting point for both bodies as the origin, and Sally's direction as the positive direction.

Centre of mass = [(60)(25) + (5)(-300)]/(60+5)

= 0 m.

The centre of mass is still at the starting point for both bodies.

c) The shore is 30 m away.

Speed = (Distance)/(time)

Time = (Distance)/(speed) = (30/2.5)

Time = 12 s

Hope this Helps!!!

7 0
2 years ago
Read 2 more answers
PLEASE HELPPP 100 POINTS HURRY !!!!Which diagram best illustrates the magnetic field of a bar magnet? A bar magnet with a north
Serggg [28]

I think this is right I hope this is right for you

7 0
2 years ago
Read 2 more answers
A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
2 years ago
Read 2 more answers
You are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As so
grigory [225]

Answer:

Explanation:

Time duration during which acceleration exists in  bicycle =

23 / 12 = 1.91 s

Time duration during which acceleration exists in car

= 47 / 8 = 5.875 s

Distance covered by bicycle during acceleration ( t = 1.91 s )

= 1/2 x 12 x (1.91)²

= 21.88 mi

Distance covered by car during this time ( t = 1.91 s )

= 1/2 x 8 x (1.91)²

7.64 mi ,

velocity of car after 1.91 s

= 8 x 1.91 = 15.28 mi/h

Let after time 1.91 , time taken by them to meet each other be t

Total distance covered by cycle = total distance covered by car

21.88 + 23 t = 7.64 + 15.28t + 4 t²

21.88 = 7.64 - 7.72t +4 t²

4 t² -7.72 t -14.24 = 0

t = 2.83 s

Total time taken

= 2.83 + 1.91

= 4.74 s

So after 4.74 s they will meet each other.

b ) Maximum distance occurs when velocity of both of them becomes equal .

Velocity after 1.91 s of bicycle

12 x 1.91 = 23 mi/h

Velocity after 1.91 s of car

8 x 1.91 = 15.28 mi/h . Let after time t , the velocity of car becomes 23

15.28 + 8t = 23

t = .965 s

So after time .965 s , car has velocity equal to that of bicycle.

The bicycle will travel a distance of

= 21.88 + .965 x 23 = 44.075 mi

car will travel a distance of

7.64 + 15.28 x .965 + .5 x 8 x .965²

= 7.64 + 14.75 + 3.72

= 26.11 mi

Distance between car and bicycle

= 44.075 - 26.11 = 17.965 mi

= 17.965 x 1760

= 31618.4 ft.

5 0
2 years ago
Three identical train cars, coupled together, are rolling east at speed v0. A fourth car traveling east at 2v0 catches up with t
aliina [53]

Answer:v_o

Explanation:

It is given that three cars has same mass m with speed v_o

suppose rest two cars also has same mass m

As there is no external force therefore momentum is conserved

Initial Momentum P_i

P_i=3mv_0+m(2v_0)+m\times 0

Final momentum P_f

P_f=5m\times v

where v=final velocity

P_i=P_f

5mv_o=5mv

v=v_o

thus final velocity is v_o

8 0
2 years ago
Other questions:
  • Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
    14·1 answer
  • If the net force acting on an object increases by 50 percent, then the acceleration of the object will
    11·1 answer
  • For each of the motions described below, determine the algebraic sign (+, -, or 0) of the velocity and acceleration of the objec
    14·1 answer
  • A 38 kg crate rests on a floor. A horizontal pulling force of 170 N is needed to start the crate
    15·1 answer
  • A 2.5-L tank initially is empty, and we want to fill it with 10 g of ammonia. The ammonia comes from a line with saturated vapor
    14·1 answer
  • A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at In a few mi
    5·1 answer
  • (a) A 15.0 kg block is released from rest at point A in the figure below. The track is frictionless except for the portion betwe
    12·1 answer
  • Timmy drove 2/5 of a journey at an average speed of 20 mph.
    8·2 answers
  • Suppose we have a radar dish that generates a strong signal that travels out to hit an asteroid 10^9 kilometres away.
    14·1 answer
  • What is the magnitude of the force between a 25μC charge exerts on a -10μC charge 8.5cm away?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!