Question

A 38 kg crate rests on a floor. A horizontal pulling force of 170 N is needed to start the crate

Answer 1

Answer:

0.456033049

Explanation:

$F=\mu N$ where N=mg hence

$F=\mu mg$ where m is mass of object, g is acceleration due to gravity whose value is taken as $9.81 m/s^{2}$, $\mu$ is the coefficient of static friction and F is the applied force.

Making $\mu$ the subject we obtain

$\mu=\frac {mg}{N}$ and substituting m for 38 Kg, g for $9.81 m/s^{2}$ and 170 N for  F we obtain

$\mu=\frac{170} {38*9.81}=0.456033049$

Therefore, the coefficient of static friction is 0.456033049