A division problem is shown below. 4 and one-third divided by 5 and StartFraction 1 over 6 EndFraction The reciprocal of a fract
2 answers:
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Answer:
Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because
Step-by-step explanation:
The complete question in the attached figure
we know that
If the length sides of a triangle, satisfy the Pythagorean Theorem, then is a right triangle
where
c is the hypotenuse (the greater side)
a and b are the legs
In this problem
The length sides squared of the triangle are equal to the areas of the squares
so
substitute
----> is not true
so
The length sides not satisfy the Pythagorean Theorem
therefore
Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because
Answer:
Step-by-step explanation:
The given system is:
Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.
This gives me the system:
We could solve the first equation for and replace the second
with that.
Let's do that.
Subtract on both sides:
So we are replacing the second in the second equation with
which gives us:
Now recall the first equation we arranged so that was the subject. I'm referring to
.
We can now find given that
using the equation
.
Let's do that.
with
:
So the solution is (8,-1).
We can check this point by plugging it into both equations.
If both equations render true for that point, then we have verify the solution.
Let's try it.
with
:
is a true equation so the "solution" looks promising still.
with
:
is also true so the solution has been verified since both equations render true for that point.