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2 years ago

A maximum can occur at the each of the following except

Mathematics

2 answers:

Vlad [161]2 years ago

8 0

Answer:

im pretty sure its B correct me if im wrong

Step-by-step explanation:

ziro4ka [17]2 years ago

5 0

I think It’s B hope it helps

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Truck A costs $600 more that Truck B. However, it burns 0.06 gallon/mile compared to 0.07 gallon/mile for truck B. Both trucks h

qwelly [4]

Answer:

1,778

Step-by-step explanation:

Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.

Truck A's cost for 10 years is ...

A = C+600 +(0.06)(2.25)(10X) -(S+200)

Truck B's cost for 10 years is ...

B = C +(0.07)(2.25)(10X) -S

We want to find X such that Truck A's cost is lower, so ...

C -S +1.35X +400 < C -S +1.575X

400 < 0.225X

1777 7/9 < X

1778 miles driven per year (or more) makes Truck A a better option.

5 0

2 years ago

Jake's morning run was a distance of 9.3 miles. He ran back and forth on one long straight street. He started at his house and r

Sergeeva-Olga [200]

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

7 0

2 years ago

The graph shows the rate at which the depth of the water in a pond is changing over time. On a coordinate plane, a graph titled