A maximum can occur at the each of the following except

In circle O, central angle AOB measures StartFraction pi Over 3 EndFraction radians. Circle O is shown. Line segments A O and B

blondinia [14]

Answer:

6(pie)

Step-by-step explanation:

trust me ; )

6 0

2 years ago

Read 2 more answers

What is the value of x if g^x-1-2= 25?

SVETLANKA909090 [29]

Answer:

Third option: $x=\frac{5}{2}$

Step-by-step explanation:

<h3> The correct exercise is attached.</h3>

The equation given is:

$9^{x-1}-2=25$

The steps to find the value of "x" are shown below:

1. Add 2 to both sides of the equation:

$9^{x-1}-2+2=25+2\\\\9^{x-1}=27$

2. Descompose 9 and 27 into their prime factors:

$9=3*3=3^2\\27=3*3*3=3^3$

3. Substitute them into the equation:

$3^{2(x-1)}=3^3$

4. Knowing that If $a^n=b^m$ , then $n=m$ , we get:

$2(x-1)=3$

5. Apply Distributive property:

$2x-2=3$

6. Add 2 to both sides:

$2x-2+2=3+2\\\\2x=5$

7. Divide both sides of the equation by 2:

$\frac{2x}{2}=\frac{5}{2}\\\\x=\frac{5}{2}$

3 0

2 years ago

Read 2 more answers

Solve ln y = kt for y

alexandr402 [8]

Y is already solved because y=kt

5 0

2 years ago

Read 2 more answers

A cell phone company is looking to place a new tower to service 3 cities. In order for it to best service each city, it needs to

omeli [17]

Answer:

circumscribed circle
The center of a circle circumscribing the triangle connecting the 3 cities will be equidistant from all three cities.

Step-by-step explanation:

The circumscribed circle or <em>circumcircle</em> of a polygon is a circle that passes through all the vertices of the polygon. The center of the circle, the circumcenter, is equidistant from all of the polygon's vertices.

The center is found at the point of intersection between the perpendicular bisectors of any two (non-parallel) chords of the circle. That is, <em>the perpendicular bisectors of any two of the sides of the triangle joining the cities will intersect at the circumcenter</em>.

The method of locating the center of the circle this way is simple and effective.

7 0

2 years ago

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

2 years ago