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Likurg_2 [28]
2 years ago
10

A railway system on a hillside moves passengers at a constant rate to an elevation of 50 m. The elevations of a train are given

for 2 different
locations.
a. Write an equation in point-slope form to represent the elevation of the train in terms of time. How can the equation be used to find the rate
of increase in elevation of the train in meters per second?
b. At what elevation does the train start initially? Write a linear equation in a form that gives the information as part of the equation. Explain
your reasoning
a. If x is the time in seconds and y is the elevation of the train in meters, then represents the elevation of the train in terms of time.
(Type an equation. Type your answer in point-slope form. Use integers or decimals for any numbers in the equation.)
Mathematics
2 answers:
Bingel [31]2 years ago
6 0

Answer:

<em>part a) y</em>

<em>-9=0.4(x-14.5)</em>

<em>part b) slope= 0.4</em>

<em>part c) 3.2 meters</em>

<em>final answer is y=0.4x+3.2( slope-intercept )</em>

Step-by-step explanation:

hope that help :)

Brut [27]2 years ago
4 0
8-4x(3x^2+5)-2(x+7) is equivalent
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Given: mKP=2mIP, mIVK =120°<br> Find: m∠KJL.
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Answer:

<h2>The measure of angle KJL is 40°.</h2>

Step-by-step explanation:

Givens

m(KP)=2m(IP)

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Notice that

m(KP)+m(IP)+m(IVK)=360\°, by definition sum of arcs.

Replacing given values, we have

2m(IP)+m(IP)+120\°=360\°\\3m(IP)=360\° - 120\°\\m(IP)=\frac{240\°}{3}\\ m(IP)=80\°

Which means m(KP)=2(80\°)=160\°

Notice that arc KP is the subtended arc by angle KJL.

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Therefore, the measure of angle KJL is 40°.

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