Given
∠ABC is an inscribed angle
Find out the m∠BDA and m∠BCA .
To proof
First find the value of the central angle ( intercepted arc measure BA)
∠BOA = 360° - 250°
= 110 °
Thus the intercepted arc AB is of measure 110°
FORMULA
thus putting the value in the above equation
we get
∠BDA = 55°
Now find out ∠BCA
In the quadilateral AOBC
As shown in the diagram AC & BD are tangent
thus
∠CAO = 90°
∠CBO = 90°
As we know the sum of a quadilateral is 360°.
thus
∠AOB + ∠CAO + ∠CBO +∠ BCA = 360°
Put the value as mentioned above
110° +90° + 90° +∠BCA = 360°
∠BCA = 360° - 290°
∠BCA = 70°
Hence proved
Answer:
The new position of the fish is = -23.05 feet
Step-by-step explanation:
We are being told that a fish is swimming 10.2 feet below the water surface
i.e. -10.2 feet
The fish then descend another 12.85 feet.
This means;
The first goes down from its first initial depth.
Mathematically, the subtraction expression that can be used to find the new position of the fish is:
= ( -10.2 + (-12.85) ) feet
Then, the new position of the fish is
= -23.05 feet
Answer:
Third one:
The experimental probability of rolling a 2 is One-fourth and the theoretical probability of rolling a 2 is One-sixth.
Step-by-step explanation:
Theoretical probability of 2:
1/6
Experimental probability of 2:
15/60 = 1/4
The answer to your question is 2
Let’s throw some numbers in here just so it becomes clear what we are asked for.
Let’s say the teacher hands out 12 notebooks that came in packs with 4 notebooks in each pack. If you are asked for the number of packs here you would see that it’s 3. That is 3 packs of 4 give 12.
So you divide the number of notebooks handed out (m) by the number of notebooks per pack (c) to get the number of packs.
The number of packs is m/c
