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Semmy [17]
2 years ago
12

An epidemiologist is observing the decay pattern of a pathogenic bacteria after applying a vaccine. He starts with 1,000 bacteri

a that decay at a rate of 8% per hour. He will check on the bacteria in 48 hours. How many bacteria will he find? Round your answer to the nearest whole number.
Mathematics
2 answers:
Radda [10]2 years ago
7 0

Answer:

21

Step-by-step explanation:

Identify the value of each variable in the formula. Be sure to put the percent in decimal form. Be sure the units match—the rate is per hour and the time is in hours.

AA0rt=?=1000=−0.08/hour=48hours

Substitute the values in the formula.

AA=A0ert=1,000e−0.08⋅48

Compute the amount.

A≈21.49

Round to the nearest whole number.

A≈21

Zielflug [23.3K]2 years ago
6 0

Answer:

8%=1 hour

?=48 hours

48×8

384

1000-384

616 bacteria

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The angle by which AB turns clockwise about point B to coincide with BC is ? degrees. If from point B, a point E is drawn direc
Oksana_A [137]
A) AB turn clockwise to coincide with BC

= ABD + DBC

= 33.3° + 30.6° 

= 63.9°


b) If E is drawn directly opposite C.

EBC is a straight line, so sum of angles =180°

ABE + ABD + DBC = 180°

ABE + 33.3° + 30.6° = 180°

ABE + 63.9° = 180°

ABE = 180 - 63.1

ABE = 116.9° 

Hope this explains it.
3 0
2 years ago
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What is the decimal multiplier to decrease by 0.6%?
Zielflug [23.3K]

Step-by-step explanation:

0.6/100= 0.006 should be multiplied to decrease by 0.6%

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2 years ago
I NEED HELP ON THIS SO BAD I WILL GIVE CROWN FOR ANSWER
Murljashka [212]

Answer: do 150ml*15 tubes is 2,250 ml

2,250/1000 is 2.25L (1L =1000ml is multiply by 1000)

7 0
2 years ago
The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda
blondinia [14]

Answer:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

\mu = 514 , \sigma =40

For this case we can use the Chebysev theorem who states that "At least 1 -\frac{1}{k^2} of the values lies between \mu -k\sigma and \mu +k\sigma"

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

4 0
2 years ago
Find a solution to the linear equation y=8x−32 by filling in the boxes with a valid value of x and y.
mario62 [17]

Answer:

Answers are below

Step-by-step explanation:

I made a table with some of the possible values for x and y.

I also graphed the equation to show the points on a graph.

If these answers are correct, please make me Brainliest!

5 0
2 years ago
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