Is analyzing a sequence challenging for you

Mathematics

2 answers:

timama [110]2 years ago

8 0

No becuse I am very educated in everything

IrinaK [193]2 years ago

3 0

Answer:

whats the point of this post?

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Three friends—Elaine, Kelly, and Shannon—all start for their college volleyball team. Each plays a different position: setter, m

gizmo_the_mogwai [7]

Answer:

Elaine is the outside hitter in Freshman Year

Kelly is the setter in Junior Year

Shannon is the middle blocker in Sophomore Year

Please mark my answer as brainiest

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2 years ago

Use the drop-down menus to complete these statements.

OverLord2011 [107]

Answer: 1/20 mile per minute 1:20

Step-by-step explanation:

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2 years ago

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three positive numbers are in Arithmetic Progression (A.P). the sum of the squares of the three numbers is 155. while the sum of

Alecsey [184]

Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.

We do not know what x and y stand for. Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2 (common difference is positive)

Therefore the three numbers of the AP are
{7-2,7,7+2}, or
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2 years ago

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical

Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

$p = \frac{78}{100} = 0.78$