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aniked [119]
2 years ago
11

Goldilocks needs to find at least 12 lb of gold and at least 18 lb of silver to pay the monthly rent. There are two mines in whi

ch Goldilocks can find gold and silver. Each day that Goldilocks spends in mine 1, she finds 2 lb of gold and 2 lb of silver. Each day that Goldilocks spends in mine 2, she finds 1 lb of gold and 3 lb of silver. Formulate an LP to help Goldilocks meet her requirements while spending as little time as possible in the mines. Graphically solve the LP.
Mathematics
1 answer:
VikaD [51]2 years ago
6 0

Answer:

cave 1 -  2g= 12 gold,  g is 6

2s  = 18 silver,  s = 9

so she would stay 9 days digging for silver and 6 for gold

cave 2-  1g = 12 gold,  g is 12

3s = 18 silver,  s = 4

she would stay 4 days looking for silver and 12 for gold

cave 1 is better because its less days since she is digging for gold and silver at same time it would only take maybe 10 days but for cave 2 its would take abt 13 days

Step-by-step explanation: idk i just put some stuff together sorrry its wrong..... but i hope it helps..

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Alex, Toby and Samuel are playing a game together.
Shalnov [3]

Answer:

1/9

Step-by-step explanation:

There are three places and three people.

Times them together for the total outcomes:

1/3 x 1/3= 1/9

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2 years ago
A scale model of a merry-go-round and the actual merry-go-round are similar. a. How many times greater is the base area of the a
Kipish [7]
The area ratio is the square of the linear dimension ratio. So if the merry-go-round base is circular, the area contains the square of the radius. If a polygon, the base can be divided into triangles. The area of each triangle involves the product of the base length and the height, so since both have the same change of length, the product will square the scaling ratio.
Let’s say the ratio of corresponding lengths is x:1 then the ratio of the base areas is x²:1.
The question doesn’t provide any figures.
Let’s put some in as an example. Let the actual merry-go-round be circular with a diameter of 20 feet, while the model is one foot in diameter. So the ratio of the actual ride and it’s model is 20:1. The area of the base of the actual ride is 100π sq ft. The area of the base of the model is π/4 sq ft. We expect the ratio of these areas to be 20²=400. 100π/(π/4)=400.
6 0
2 years ago
The radius of circle G is 4 cm. What is the tangent
qaws [65]
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Likurg_2 [28]
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6 0
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Read 2 more answers
Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm
madreJ [45]

Answer:

See explanation

Step-by-step explanation:

1 step: \overline{GI}\cong \overline {JL} - given

2 step: \overline{GI}\cong \overline{GH}+\overline{HI} - Segments Addition Postulate

3 step: \overline{GH}+\overline{HI}\cong \overline {JL} - Substitution Property

4 step: \overline {JL}\cong \overline {JK}+\overline {KL} - Segments Addition Postulate

5 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {KL} - Substitution Property

6 step: \overline{GH}\cong \overline {KL} - given

7 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {GH} - Substitution Property of Equality

8 step: \overline{HI}\cong \overline {JK} - Subtraction Property of Equality

3 0
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