Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
Answer:
6 hours
Step-by-step explanation:
Let both of them plan for t hours to plant 111 trees n t hours
Melissa can plants 10 trees in 1 hour
in t hours she can plant 10 t trees
Jane plants 17 tree in 2 hours
in one hour Jane can plant 17/2 trees
in t hours she can plant (17/2)t trees.
Total trees planted by both of them in t hours in terms of t will be
10t + (17/2)t
= (10t*2 + 17t)/2
= (20t + 17t)/2
= 37t/2
but it is given that they planted 111 trees together
so 37t/2 should be equal to 111
37t/2 = 111
=> 37t = 111*2 = 222
=> t = 222/37 = 6.
Thus, it takes 6 hours for both of them to plant 111 trees together.
Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase
given
h=9
v=324pi
324pi=9(basearea)
divide both sides by 9
36pi=areabase
the area of the base is 36pi square cm (put 36 in the blank since the pi is already there)