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ivanzaharov [21]
2 years ago
8

a photo collage consists of seven equal sized square photo arranged in a row to form a rectangle if the total area of the colleg

e is 567 square inches what is the length of the collage

Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

Step-by-step explanation:

I have attached a written explanation to help :).

Let's say each side of the square =x

If we put 7 squares in a row to make the rectangle,

length of the rectangle = 7x

Area of a rectangle = length multiplied by width

Area of rectangle =  7x multiplied by x = 7x^2

We are also told that the total area = 567

So 7x^2 = 567

Now solve for x.

Divide both sides by 7.

\frac{7x^2}{7} = \frac{567}{7}

x^2 = 81

Then square root both sides to find x

x = \sqrt{81} = 9

Finally, the question asks to find the length of the collage which we said was 7x and we know x = 9

Length of collage = 7x  = 7 multiplied by 9 = ?

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In an exam 35 out of 125 students failed. What percentage passed the exam?​
kotegsom [21]

Answer:

28%

Step-by-step explanation:

To find the percentage, you first have to divide:

35 out of 125 Which is 35 ÷ 125 = 0.28

Then you must convert that into a percentage:

0.28 = 28%

Hope this helps you out! : )

4 0
2 years ago
a triangle has sides of 4 and 6 units. The measurement of the longest side is missing.Ted says that one possibility for the unkn
tester [92]
This is called the pythagorean theorem: a^2 + b^2 = c^2.
Basically, the sum of one side squared + the side of another side squared = the length of the longest side (or hypotenuse).

We have to do the following math:
4 * 4 = 16
6 * 6 = 36
16 + 36 = 52.

We know that 52 = c^2
So we have to \sqrt{c} to get 7.21

You do not agree with Ted. 

7 0
2 years ago
If you have a stack of pennies without counting them how do you know if there is an even or odd number of them
zavuch27 [327]

If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.

Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.

Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies. After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.

5 0
2 years ago
Find all the zeros of the equation 12x^2-64=-x^4
Natalija [7]

Answer: all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

Step-by-step explanation:

Since we  have given that

12x^2-64=-x^4\\\\x^4+12x^2-64=0

We need to find the zeroes of the above equation.

So, we will use  "Split the middle terms" :

x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)

So, all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

7 0
2 years ago
If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i
nadya68 [22]

Answer:

  • 12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

  • 28 - 4 = 24
  • 39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

  • 24 = 2*2*2*3
  • 36 = 2*2*3*3
  • GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0
1 year ago
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