These are the <span>xx</span> and <span>yy</span> intercepts of the equation <span><span>2x−5y=6</span><span>2x-5y=6</span></span>.x-intercept: <span><span>(3,0)</span><span>(3,0)</span></span>y-intercept: <span>(0,−<span>65</span><span>)
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solution:
Lets start with the most amount that could have been sold.......using guess and check, we can figure out that 290 salads could have been sold, while 8 cartons of milk would have been sold.
The least amount of salads that could have been sold were none.
so,
you have 0<s<290
at least none were sold, and at most 290 were sold
but I do believe you are missing part of the question
Answer:
Hello some parts of your question is missing below is the missing part
c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces
Answer: A) 0.0099
B) 0.6796
C) 0.13956
Step-by-step explanation:
weight of Navel oranges evenly distributed
mean ( u ) = 8 ounces
std ( б )= 1.5
navel oranges = X
A ) percentage of oranges weighing more than 11.5 ounces
P( x > 11.5 ) = 
= P ( Z > 2.33 ) = 0.0099
= 0.9%
B) percentage of oranges weighing less than 8.7 ounces
P( x < 8.7 ) = 
= P ( Z < 0.4667 ) = 0.6796
= 67.96%
C ) probability of orange selected weighing between 6.2 and 7 ounces?
P ( 6.2 < X < 7 ) = 
= P ( -1.2 < Z < -0.66 )
= Ф ( -0.66 ) - Ф(-1.2) = 0.13956