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Drupady [299]
2 years ago
7

Outline are effective because they?

Business
1 answer:
notka56 [123]2 years ago
6 0
They help you write better and faster.
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Privo Co. purchases a machine that cost $15,000. Privo estimates a 5-year life with no salvage value. The first three years of d
Ierofanga [76]

Answer:

Double-declining balance method

Explanation:

First we have to find the depreciation rate which is shown below:

= One ÷ useful life

= 1 ÷ 4

= 20%

Now the rate is double So, 40%

In year 1, the original cost is $15,000, so the depreciation is $6,000 after applying the 50% depreciation rate

And, in year 2, the depreciation is ($15,000 - $6,000) × 40% = $3,600

And, in year 3, the depreciation is ($15,000 - $6,000 - $3,600) × 40% = $2,160

6 0
2 years ago
On may 1, the cash account balance was $72,600. during may, cash receipts totaled $345,600 and the may 31 balance was $95,230. d
Sphinxa [80]
<span>$322,970 The expression for the cash balance at the end of the month is B = I + R - P where B = Balance at the end of the month. I = Initial balance at the beginning of the month. R = Receipts received during the month. P = Payments made during the month. So let's substitute the known values we have and solve for P B = I + R - P 95230 = 72600 + 345600 - P 95230 = 418200 - P 95230 + P = 418200 P = 322970 So the cash payments made were $322,970</span>
4 0
2 years ago
Dan purchases a 1000 par value 10-year bond with 9% semiannual couponsfor 925. He is able to reinvest his coupon payments at a n
damaskus [11]

Answer:

9.2%

Explanation:

Missing word <em>"Calculate his nominal annual yield rate convertible semiannually over the ten-year period"</em>

Semi annual coupon payments = 9% / 2 = 4.5%

Par value = 4.5% * 1,000 = $45

interest rate per period = r = 7% / 2 = 3.5%

Number of periods, n = 2 x 10 = 20

FV of all the coupons reinvested = 45 / r * [(1 + r)^n - 1]

FV of all the coupons reinvested = 45 / 3.5% * [(1 + 3.5%)^20 - 1]

FV of all the coupons reinvested = $1,272.59

Receipt of par value at the end of the 10 years = par value = 1,000

Total accumulated value at the end of 10 years =  $1,272.59 + 1,000

Total accumulated value at the end of 10 years = $2,272.59

Invested amount = $925

i = nominal interest convertible semi annually.

$925 * (1 + i / 2)^n = 2,272.59  

925 * (1 + i / 2)^20 = 2,272.59

i = 2 * [(2,272.59 / 925)^1/20 - 1]

I = 9.19%

I = 9.2%

So, his nominal annual yield rate convertible semiannually over the ten-year period is 9.2%

7 0
1 year ago
Selected sales and operating data for three divisions of different structural engineering firms are given as follows: Division A
USPshnik [31]

Answer:

20% is the ROI of division A

8% is the ROI of division B

16% is the  ROI of division C

Explanation:

Find the attachments for the explanation

7 0
2 years ago
Fullerton Waste Management purchased land and a warehouse for $720,000. In addition to the purchase price, Fullerton made the fo
g100num [7]

Answer:$813,000

Explanation:

The cost of property plants and equipment in relation to IAS 16 includes the purchase price, related tax, transportation, professional fee, first insurance cost, and all other costs incurred to put the property in a position to be put into the desired use. The cost also includes all related miscellaneous cost.

8 0
2 years ago
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