Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence interval 
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of 
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that 
and 
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So 
= 0.05, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The correct answer is
(0.0128, 0.0532)
<span>sin(x-y) = (24-14*sqrt(2))/75
Write down what you know
sin(x) = 1/3
sec(y) = 25/24
cos(y) = 1/sec(y) = 24/25
cos(x) = sqrt(1-sin(x)^2) = sqrt(1-1/9) = sqrt(8/9) = 2*sqrt(2)/3
sin(y) = sqrt(1-cos(y)^2) = sqrt(1-576/625) = sqrt(49/625) = 7/25
We now know the sin and cos of both x and y.
Now to get the sin of x-y.
sin(x-y) = sin(x)cos(y) - cos(x)sin(y)
Substitute the known values for sin and cos of x and y, then evaluate and simplify
sin(x-y) = (1/3)(24/25) - (2*sqrt(2)/3)(7/25)
sin(x-y) = 24/75 - 14*sqrt(2)/75
sin(x-y) = (24-14*sqrt(2))/75</span>
Answer:65536
4^10/4^2
4*4=16
4*4*4*4*4*4*4*4*4*4=1048576
1048576/16=65536
Answer:
The next time both will leave the bus station at the same time is 7:15 a.m.
Step-by-step explanation:
Since 15 and 75 are multiples to each other.
So, L.C.M. of 15 and 75 is 75.
So, after 75 minutes both buses will leave the station at the same time.
Also since buses begin their routes at 6 a.m.
So, next time they will meet at
6 hours 0 minutes + 75 minutes = 7 hours 15 minutes = 7:15 a.m.
