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irakobra [83]
2 years ago
9

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –

6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

Given:

The inequality is

-3(2x-5)

To find:

The correct representations of the given inequality.

Solution:

We have,

-3(2x-5)

Using distributive property, we get

-3(2x)-3(-5)

-6x+15

Therefore, the correct option is C.

Isolate variable terms.

15-10

5

It means, the value of x is greater than 5.

Since 5 is not included in the solution set, therefore, there is an open circle at 5.

So, the graphical represents of the solution is a A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Therefore, the correct option is D.

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Josiah owns a food truck that sells tacos and burritos. He only has
bogdanovich [222]

Answer:

Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.

Step-by-step explanation:

Given , Josiah owns a food truck that sells tacos and burritos.

He sells each burritos for $7.50. If 79 burritos were sold.

Then the price of 79 burritos is $(7.50×79) =$592.50

Let x tacos were sold.

He sells each tacos for $5.

Then the price of x tacos is = $(x × 5)=$5x

Also given that Josiah must sell a minimum of $930 worth of tacos and burritos.

Therefore,

5x+592.50≥ 930

⇔5x≥930-592.50

⇔5x≥337.5

⇔x≥67.5

But he only has enough supplies to make 149 tacos or burrito.

He already sold 79 burrito.

So, remain space for tacos is = (149-79) = 70

So,67.5≤x≤70

∴x = 68 or 69 or 70

Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.

8 0
2 years ago
The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
Kruka [31]

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,\lambda = 20

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=0.0516

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516

8 0
2 years ago
The correlation coefficient for the ages of drivers in a driver safety class and the number of traffic violations they have rece
Doss [256]
A correlation coefficient is always a value in between -1 and 1
The closest a coefficient to -1, the correlation is a strong negative correlation
The closest a coefficient to 1, the correlation is a strong positive correlation
The closest a coefficient to 0, there is no correlation at all

The coefficient -0.61 shows a strong negative correlation
This means that the relationship between the age and the violation is an inverse relationship; as age increases, violation decreases

Answer: option C
7 0
2 years ago
Which table shows a constant rate of change of –3? A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6.
Andrew [12]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
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Steve stayed after school for extra activities 55% of the 180 school days this year. How many days did Steve stay after school?
musickatia [10]

Answer:

11/20 or 99/180 days

Step-by-step explanation:

55/100 converted to ?/180

180/100=1.8

so you would do the same on the numerator which is 55*1.8=99

99/180= 33/60=11/20

7 0
2 years ago
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