Answer:
130 ± 1.82 inches i.e the range of the values is 128.18 inches to 131.82 inches.
Step-by-step explanation:
The range of values required here implies the values fall between the least and maximum values.
Since the values can vary by 1.4%, the range can be determined by:
1.4% of 130 = 
x 130
= 0.014 x 130
= 1.82
The addition or subtraction of 1.82 to/from 130 inches gives the required range.
i.e the range of allowable values = 130 ± 1.82 inches.
Thus,
130 - 1.82 = 128.18 inches
130 + 1.82 = 131.82 inches
The values falls between 128.18 inches to 131.82 inches.
Answer: 7 over 24 I think so! Sorry I didn’t reduce
Step-by-step explanation:
<u>Answer:</u>
If PQ=RS then PQ and RS have the same length. Hence option D is correct
<u>Solution:</u>
Given that, pq = rs
And, we have to find which of the given options are true.
<u><em>a) pq and rs form a straight angle
</em></u>
We can’t decide the angle in between pq and rs just by the statement pq = rs.
So this statement is false.
<u><em>b) pq and rs form a zero angle.
</em></u>
We can’t decide the angle in between pq and rs just by the statement pq = rs.
So this statement is false.
<u><em>c) pq and rs are same segment.
</em></u>
If two things equal then there is no condition that both represents a single item.
So this statement is false.
<u><em>d) pq and rs have the same length
</em></u>
As given that pq = rs, we can say that they will have the same length
Hence, option d is true.
Answer:
(k-h)(x) = 4x - 8
Step-by-step explanation:
We know Profit = Revenue - Cost
Basically we gotta subtract cost function from revenue function and get the profit function.
The cost function is h(x) = 5x + 6
The revenue function is k(x) = 9x - 2
Hence, Profit is:
(k-h)(x) = (9x - 2) - (5x + 6)
(k-h)(x) = 9x -2 - 5x - 6
(k-h)(x) = 4x - 8
<h3>
Answer:</h3>
equations
solution
<h3>
Step-by-step explanation:</h3>
Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:
... 20a +10c = 15000 . . . . . . total revenue from ticket sales
... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold
Using the expression for c, we can substitute into the first equation to get ...
... 20a +10(3a) = 15000
... 50a = 15000
... a = 15000/50 = 300 . . . . . adult tickets sold
... c = 3·300 = 900 . . . . . children's tickets sold
