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Elina [12.6K]
2 years ago
10

Jason bought 10 of the 30 raffle tickets for a drawing. What is the probability that Jason will win all 3 of the prizes if once

a raffle ticket wins a prize it is thrown away? StartFraction 6 over 203 EndFraction StartFraction 1 over 27 EndFraction StartFraction 3 over 29 EndFraction StartFraction 1 over 9 EndFraction
Mathematics
1 answer:
svet-max [94.6K]2 years ago
7 0

Given:

Total of raffle tickets = 30

Number of tickets Jason bought = 10

Number of prizes = 3

To find:

The probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away.

Solution:

Total of raffle tickets = 30

Number of prizes = 3

So, number of total outcomes is

n(S)=^{30}C_3

Number of tickets Jason bought = 10

So, number of favorable outcomes is

n(A)=^{10}C_3

Now,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

\text{Probability}=\dfrac{n(A)}{n(S)}

\text{Probability}=\dfrac{^{10}C_3}{^{30}C_3}

\text{Probability}=\dfrac{\dfrac{10!}{(10-3)!3!}}{\dfrac{30!}{(30-3)!3!}}

\text{Probability}=\dfrac{10\times 9\times 8\times 7!}{7!3!}\times\dfrac{27!3!}{30\times 29\times 28\times 27!}

\text{Probability}=\dfrac{10\times 9\times 8}{30\times 29\times 28}

\text{Probability}=\dfrac{6}{203}

Therefore, the correct option is A.

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Diego's sister is twice his age minus 9 years. She is also as old as half the sum of the ages of Diego and both of his 12-year-o
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Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
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Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

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After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

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Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

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Z = \frac{16.2 - 14.4}{0.1}

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Z = 18 has a pvalue of 0.9999.

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