No their babies won't look alike.
<h3>Explanation:</h3>
Both the couples mentioned here i.e. Sally - Harry and Emily - Ken are both identical twins. So they have similar pairs of genetic setup. This was possible because they developed from same zygote.
But during gametogenesis, crossing over and independent assortment occurs which brings about variation in genetic setup among the offspring. And it's very less probable that same crossing over will occur between the gametes of these couples. So, their offsprings won't look same.
Answer:
This question seem incomplete
Explanation:
This question seem incomplete. However, if the strand of the second fragment is what is provided above, then the answer is <em>51</em>
This strand/fragment is definitely a DNA strand because of the absence of uracil (U) or because of the presence of thymine (T). The four bases in a DNA are adenine (A), Thymine (T), cytosine (C) and Guanine (G). These bases also bind to one another in the pattern described below
A ⇆ T
G ⇆ C
Hence, the adenine (A) on one strand can only bind to thymine (T) on the complementary strand (and vice versa) while the guanine (G) on one strand can only bind to cytosine (C) on the complementary strand (and vice versa).
Hence, the letters seen is the question are representations of bases in a DNA strand/fragment. The number of letters/bases here are <em>51</em>
I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
a = 1 m/s / 0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
F = (80 g / 1000 g/kg) x (5 m/s²)
= 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force.
<span>A joint united by dense fibrocartilaginous tissue that usually permits a slight degree of movement is a symphysis.</span>
Answer:
The average density of deer in 1923 was 1 deer per 8 acres
Explanation:
Given -
In 1923, the population of deer rose to 
The density of any species is equal to total population divided by total area of the land in which this population is residing.
Where d represents the density
P represents the population and
A represents the area of land
Substituting the given values in above equation, we get -
Thus, the average density of deer in 1923 was 1 deer per 8 acres
