Answer:
-4.99
1.9435
3.25E4
1.56e-9
Step-by-step explanation:
Answer:
a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)
=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363
hence probability that it actually contains explosives given identified as containing explosives)
=(10/(4*106))*0.95/0.005002363=0.000475
b)
let probability of correctly identifying a bag without explosives be a
hence a =0.99999763 ~ 99.999763%
c)
No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,
Answer:


And the confidence interval for the difference is between:

Step-by-step explanation:
We have the following info given:
sample mean for medium Pizzas from Prim's
sample mean for medium Pizzas from Pizza Place
sample deviation for Prim's
sample deviation for Pizza Palca
sample size selected for each case
The confidence interval for the difference of means is given by:

And for the 95% confidence we need a significance level of
and
, the degrees of freedom are given by:

And the critical value would be

And replacing we got:


And the confidence interval for the difference is between:

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.
Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.
For the second question:
I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.
So, the answers are: A) and D).
I 11 x - 22 I > 22
∴ 11x-22 > 22 OR (11x -22) < -22
∴ 11 x > 44 :::::::: 11x - 22 < -22
x > 4 :::::::: x < 0
∴ x ∈ ( -∞ , 0 ) ∪ ( 4 , ∞)
∴ The correct choice is number 1
The solution is attached in the figure