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Mariulka [41]
2 years ago
3

Jonah was standing at an elevation somewhere between Negative 1 and one-half and Negative 2 and one-third meters with regards to

sea level. Which number could be Jonah’s elevation with regards to sea level?
A number line going from negative 3 to positive 3 in increments of 1.
1 and StartFraction 5 Over 6 EndFraction meters
Negative 2 and StartFraction 3 Over 6 EndFraction meters
2 and StartFraction 3 Over 6 EndFraction meters
Negative 1 and StartFraction 5 Over 6 EndFraction meters
Mathematics
2 answers:
kow [346]2 years ago
5 0

Answer

im not sure but i think its the 3rd one

Step-by-step explanation:

castortr0y [4]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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There are several ways you might think you could enter numbers in WebAssign, that would not be interpreted as numbers. N.B. Ther
Viefleur [7K]

Answer:

-4.99

1.9435

3.25E4

1.56e-9

Step-by-step explanation:

6 0
2 years ago
A train station has installed a system for determining whether bags contain explosives. It has a 95% chance of correctly identif
astraxan [27]

Answer:

a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)

=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363

hence  probability that it actually contains explosives given identified as containing explosives)

=(10/(4*106))*0.95/0.005002363=0.000475

b)

let probability of correctly identifying a bag without explosives be a

hence a =0.99999763 ~ 99.999763%

c)

No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,

3 0
2 years ago
The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau
AleksandrR [38]

Answer:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

Step-by-step explanation:

We have the following info given:

\bar X_1 = 240 sample mean for medium Pizzas from Prim's

\bar X_2 = 210 sample mean for medium Pizzas from Pizza Place

s_1 =8.6 sample deviation for Prim's

s_2 =5.7 sample deviation for Pizza Palca

n_1 =n_2 = 100  sample size selected for each case

The confidence interval for the difference of means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

And for the 95% confidence we need a significance level of \alpha=1-0.95=0.05 and \alpha/2 =0.025, the degrees of freedom are given by:

df= n_1 +n_2 -2= 100+100-2 =98

And the critical value would be

t_{\alpha/2}= 1.984

And replacing we got:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

8 0
2 years ago
For making a scatter plot of the data set, which would be the best scale and interval for the axis that represents the amount of
Serga [27]

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.

Because, you can't just have 1 to 4, as some of the numbers are less than 1.  Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.

For the second question:

I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.

So, the answers are: A) and D).

8 0
2 years ago
Question and answer choices are in the screenshot. THANK YOU!!
Anika [276]
I 11 x - 22 I > 22
∴ 11x-22 > 22          OR          (11x -22) < -22
∴ 11 x > 44             ::::::::          11x - 22 < -22
    x > 4                   ::::::::              x < 0

∴ x ∈ ( -∞ , 0 ) ∪ ( 4 , ∞)
∴ The correct choice is number 1
The solution is attached in the figure

5 0
2 years ago
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