Question

Arjun had some chocolates with him. He gave one fourth of them to Arun and one-sixth of them to Varun. Arjun could do so without breaking any chocolate. Which of these could be the number of chocolates Arjun had in the beginning?

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Given

Arun = ¼

Varun = ⅙

Required

Determine the possible initial number of chocolate

The question requires options to work with which are missing; however, I'll explain how to solve and also list out possible options to make use of.

The question says Arjun gave out fractions of his chocolate without breaking an of them; this means that he gave out whole chocolate (i.e. whole number)

So, to solve this, we multiply the fraction given to Arun and Varun.

Any of the options that results in non decimal integer answers the question.

Take for instance, the options are:

a) 8 b) 15 c) 20 d) 48

Option A: 8

Arun = ¼ * 8 = 2

Varun = ⅙ * 8 = 1.33

Option B: 15

Arun = ¼ * 15 = 3.75

Varun = ⅙ * 15 =2.5

Option C: 20

Arun = ¼ * 20 = 5

Varun = ⅙ * 20 = 3.33

Option D: 48

Arun = ¼ * 48 = 13

Varun = ⅙ * 48 = 8

Option D answers the question because other options resulted in decimals for either Arun or Varun or both of them.