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2 years ago

4

Use the diagram to find the length. PB is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD

.
Given BD = 16 and PC = 10, find PB.
PB =

1 answer:

castortr0y [4]2 years ago

4 0

Answer:

<em>6 units</em>

Step-by-step explanation:

BC = BD/2 = 8

PB² + 8² = 10²

PB² = 100 - 64 = 36 ⇒ PB = <em>6 units</em>

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The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

so

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

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2 years ago

You are in charge of a crew that inspects cars. Each car takes approximately 1/2 hour for 1 person to inspect. The normal crew h

jonny [76]

Answer:

Each inspectors NEEDS to work 20 hours in order to review 320 cars.

Step-by-step explanation:

The amount of time taken to inspect 1 car = 1/2 hr = 0.5 hr

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But 2 people are MISSING.

So, the total number of present people in crew = 10 - 2= 8

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Since each car takes 0.5 hour to be reviewed.

So, the time required to review 320 cars = 320 x 05 = 160 hours.

So, the total hours needed to inspect all 320 cars = 160 hours

Now,as there are total 8 crew members.

$\implies \textrm{The number of hours each inspector needs to work} = \frac{\textrm{Total working hours needed}}{\textrm{Toal number of inspectors}} \\= \frac{160}{8} = 20$

Hence , each inspectors NEEDS to work 20 hours in order to review 320 cars.

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Answer:

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You just find the total weight and divide it by the number of weights

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