To solve this, we must first find out the cost-per-ounce of a cup of coffee. Assuming that the rates are flat, then we can just divide the 8-dollar-cost by the 4-ounce cup that it buys.
8 / 4 = 2
The cost-per-ounce of a cup of coffee is $2.
Now, we just have to multiply the cost-per-ounce by the amount of coffee we want to find out the cost of.
2 * 3 = 6
With all else constant, a 3-ounce cup of coffee would cost $6.
Hope that helped! =)
You need to solve for one variable in equation 1 and substitute it in equation 2 to solve.
Equation 1: x+y=24
x= number of 3 pt questions
y= number of 5 pt questions
24= Total number of questions
Equation 2: 3x+5y=100
100= Total point value possible on test
3x= point value of 3 pt questions
5y= point value of 5 pt questions
x+y=24
Subtract y from both sides
x=24-y
Substitute in equation 2:
3x+5y=100
3(24-y) +5y=100
72-3y+5y=100
72+2y=100
Subtract 72 from both sides
2y=28
Divide both sides by 2
y=14
Substitute y=14 back in to solve for x:
3x+5y=100
3x+5(14)=100
3x+70=100
Subtract 70 from both sides
3x=30
Divide both sides by 3
x=10
So there are 10 three point questions
There are 14 five point questions.
Hope this helped! :)
For this case we have the following number:
96
We can rewrite this number in an equivalent way.
For example, we can use words to rewrite the number.
We have then:
96 = ninety six
Answer:
the name of an equivalent name for 96 is:
Ninety-six
Answer:
4
Step-by-step explanation:
Given that :
Clients are interviewed in groups of 2 on the first day; meaning two persons at a time
Second day, clients are interviewed in groups of 4; meaning 4 persons at a time.
Therefore, if the same number of clients are to be interviewed on each day, the smallest number of clients that could be interviewed each day could be obtained by getting the Least Common Multiple of both numbers: 2 and 4
- - - - 2 - - - 4
2 - - - 1 - - - 2
2 - - - 1 - - - 1
Therefore, the Least common multiple is (2 * 2) = 4
Therefore, the smallest number of clients that could be interviewed each day is 4.
Answer:
(a) The probability of more than one death in a corps in a year is 0.1252.
(b) The probability of no deaths in a corps over 7 years is 0.0130.
Step-by-step explanation:
Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.
The random variable 
.
The probability function of a Poisson distribution is:
(a)
Compute the probability of more than one death in a corps in a year as follows:
P (X > 1) = 1 - P (X ≤ 1)
= 1 - P (X = 0) - P (X = 1)
Thus, the probability of more than one death in a corps in a year is 0.1252.
(b)
The average deaths over 7 year period is: 
Compute the probability of no deaths in a corps over 7 years as follows:
Thus, the probability of no deaths in a corps over 7 years is 0.0130.
