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Evgesh-ka [11]
1 year ago
5

On the coordinate plane below, quadrilateral 1 has been transformed to form quadrilateral 2.

Mathematics
1 answer:
babymother [125]1 year ago
3 0

Answer:

Step-by-step explanation:

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A drawing of a surfboard in a catalog shows its length as 8 4/9 inches. Find the actual length of the surfboard if 1/2 inch leng
jonny [76]
3/8 of a foot = 3/8 x 12/1  or 4  1/2 inches

So our 1/2 inch grows by a factor of 9  because 4 1/2 ÷ 1/2 = 9  Think how many 1/2 dollars are in 4  1/2 dollars.  (Answer is 9)

So our 8 4/9 in the catalog has to grow the same

8  4/9   x 9  = 8  4/9  x 9/1 = 76/9 x 9/1  or 76 inches which is 6 ft 4 inches.
(76 ÷12 = 6 r4)

6 0
1 year ago
Given triangle GHJ, the measure of angle G equals 110°, the measure of angle J equals 40°, and the measure of angle H equals 30°
tester [92]

Answer:

Since angle G is  

✔ the largest

 angle, the opposite side, JH, is  

✔ the longest side

. The order of the side lengths from longest to shortest is  

✔ HJ, GH, and GJ

.

Step-by-step explanation:

5 0
1 year ago
Read 2 more answers
A store sells a certain tile for $2 per tile and a pint of paint for $3. A second store sells the same items for $1 per tile and
andreev551 [17]

Answer:

2 x plus 3 y equals 26. X plus 4 y equals 18

Step-by-step explanation:

Number of tiles, = x

Number of pints of paint, = y

Store 1:

Cost per tile = $2 ; cost per pint = $3 ; total cost = $26

Store 2 :

Cost per tile = $1 ; cost per pint = $4 ; total cost = $18

System of equation:

2x + 3y = 26 - - - (1)

x + 4y = 18 - - - - - (2)

7 0
1 year ago
A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

M = z\frac{\sigma}{\sqrt{n}}

0.0001 = 2.327\frac{0.0003}{\sqrt{n}}

0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

7 0
1 year ago
Solve 9/11 + 3/13 × 26/33 - (21/121÷ 71/111)
Julli [10]

Answer:

0.72 or 0.72866953788  0.7  0.72866953788

3 0
1 year ago
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