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Yuri [45]
2 years ago
11

Write a script that inputs a line of encrypted text and a distance value and outputs plaintext using a Caesar cipher. The script

should work for any printable characters.An example of the program input and output is shown below:Enter the coded text: Lipps${svph% Enter the distance value: 4 Hello world!# Request the inputscodedText = input("Enter the coded text: ")distanceValue = int(input("Enter the distance value: "))# Calculate the decryptionplainText = ""for cr in code:ordvalue = ord(ch)cipherValue = ordvalue - distanceif cipherValue < ord('a'):cipherValue = ord('z') - \ (distance - (ord('a') - ordvalue - 1))plainText += chr(cipherValue)print(plainText)
Computers and Technology
1 answer:
jenyasd209 [6]2 years ago
4 0

Answer:

# Request the inputs

codedText = input("Enter the coded text: ")

distance = int(input("Enter the distance value: "))

# Calculate the decryption

# see comment for the rest. Brainly won't let me save an answer which contains code.

Explanation:

Above is your program fixed, but it is unclear on how to deal with unprintable characters, i.e., characters that originally were near the highest printable character ('~')

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Answer:

Start the algorithm and check the weight of the ship. Load the crystalline to the ship. Check to see if the ship weighs ship weight + k pound crystalline, if less, add more crystalline. If excess, remove the excess crystalline, but if the weight meets the condition, then take off with the loaded ship to planet sigma.

Explanation:

The algorithm continuously checks the weight of the ship on loading with the calculated sum of the ship and k pound crystalline weight. The ship is able to load the correct maximum amount of crystalline to the planet sigma.

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2 years ago
Which of the following statements does not contain an error?
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III is correct .... esc code use \
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Cardinality ratios often dictate the detailed design of a database. The cardinality ratio depends on the real-world meaning of t
Otrada [13]

Solution :

ENTITY 1               CARDINALITY RATIO                                     ENTITY 2

1. Student                        1 to many                                     Social security card

                      A student may have more than one          

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                      same unique social security number),

                     and every social security number belongs

                   to a unique.

2. Student                   Many to Many                                    Teacher

                    Generally students are taught by many

                    teachers and a teacher teaches many students.

3.ClassRoom               Many to Many                                   Wall

                      Do not forget that the wall is usually

                      shared by adjacent rooms.

4. Country                 1 to 1                                             Current President

                       Assuming a normal country under normal

                       circumstances having one president at a

                      time.

5. Course               Many to Many                               TextBook

                        A course may have many textbooks and

                       text book may be prescribed for different

                      courses.

6. Item                             Many to Many                           Order

                        Assuming the same item can appear

                         in different orders.

7. Student                       Many to Many                          Class

                        One student may take several classes.

                        Every class usually has several students.

8. Class                                 Many to 1                             Instructor

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                        instructor. In case instructors were allowed

                        to team teach, this will be many-many.

9. Instructor                  1 to 1                                             Office

                       Assuming every instructor has only one

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                     shared by 2 instructors, the relationship

                    will be 2-1. Conversely, if any instructor has a joint

                    appointment and offices in both departments,

                    then the relationship will be 1-2. In a very general

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10. E-bay Auction item             1-Many                           E-bay bid

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7 0
2 years ago
There are many different types of hardware devices, different manufacturers, and countless configuration possibilities. Explain
erik [133]

Because, they are all required to configure to it to be recognized by an operating system.

Explanation:

It is the Operating System Software that instructs the hardware and puts them together to work well. When the manufacturer does not configure the device to be recognized by an operating system, then it will not work with other components.

Example.

If an Apple machine's sound card is being put in an HP machine which uses Microsoft designed operating system, won't work due to the operating system that the sound card has been designed for.

6 0
2 years ago
Create an array w with values 0, 0.1, 0.2, . . . , 3. Write out w[:], w[:-2], w[::5], w[2:-2:6]. Convince yourself in each case
larisa86 [58]

Answer:

w = [i/10.0 for i in range(0,31,1)]

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

Explanation:

List slicing (as it is called in python programming language ) is the creation of list by defining  start, stop, and step parameters.

w = [i/10.0 for i in range(0,31,1)]

The line of code above create the list w with values 0, 0.1, 0.2, . . . , 3.

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

since start, stop, and step parameters are not defined, the output returns all the list elements.

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[:-2] since  stop is -2, the output returns all the list elements from the beginning to just before the second to the last element.

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[::5] since  step is -2, the output returns  the list elements at index 0, 5, 10, 15, 20, 25,30

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

the output returns the list elements from the element at index 2  to just before the second to the last element, using step size of 6.

6 0
2 years ago
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