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1 year ago

Find the value of x please also this is geometry

Mathematics

1 answer:

Zolol [24]1 year ago

7 0

Given:

A figure of a triangle.

To find:

The value of x.

Solution:

In a triangle, angle bisectors intersect each other at a point which is know as incenter. This point is equidistance form the each side.

Using the above property, we get

$4x-2=6x-8$

$4x-6x=2-8$

$-2x=-6$

Divide both sides by -2.

$x=\dfrac{-6}{-2}$

$x=3$

Therefore, the value of x is 3.

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Using the information given, select the statement that can deduce the line segments to be parallel. If there are none, then sele

Alina [70]

we know that

1) If the line segment AB is parallel to the line segment DC

then

m∠1=m∠D -------> by corresponding angles

2) If the line segment AD is parallel to the line segment BC

then

m∠3=m∠B -------> by corresponding angles

5 0

2 years ago

Read 2 more answers

Randi and her sister made balloon animals and sold the for. $0.50 each at the school carnival. They made $48.00. If Randi made t

evablogger [386]

Answer:

Balloon made by Randi's sister $=32$

Balloon made by Randi $=64$

Step-by-step explanation:

Let Randi's sister made $x$ balloons.

Balloons made by Randi $=2\times x=2x$

total ballons $=x+2x=3x$

$1$ cast of $1$ ballon $=\$0.50$

Cost of $x$ balloons $=3x\times0.50=1.5x$

Given total money made $=\$48.0$

$1.5x=48\\\\x=\frac{48}{1.5}\\\\x=32$

ballon made by Randi's sister $=32$

Ballon made by Randi's = $2\times32=64$

5 0

2 years ago

a 12 foot tall building casts on 8 foot long long shadow. how long of a shadow will a 5 foot tall women have

grin007 [14]

This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.

7 0

2 years ago

contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lots

Tju [1.3M]

The houses can be placed in 362,880 ways.

Step-by-step explanation:

The 9 houses are each in different design.

The each lot can place any of the 9 houses.

The 1st lot can place anyone house of all the 9 houses.
The 2nd lot can place one of remaining 8 houses.
The 3rd lot can place one of remaining 7 houses.

Similarly, the process gets repeated until the last house is placed on a lot.

From the above steps, it can be determined that :

The number of ways to place the 9 houses in 9 lots = 9!

⇒ 9×8×7×6×5×4×3×2×1

⇒ 362880 ways.

Therefore, the houses can be placed in 362880 ways.

5 0

2 years ago

The number of messages that arrive at a Web site is a Poisson distributed random variable with a mean of 6 messages per hour. Ro

QveST [7]

Answer:

a) There is a 16.0623% probability that 5 messages are received in 1 hour.

b) There is a 11.5880% probability that 10 messages are received in 1.5 hours.

c) There is a 22.4042% probability that 2 messages are received in 0.5 hours.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have a mean of 6 messages per hour.

(a) What is the probability that 5 messages are received in 1 hour?

Find the value of P when $x = 5$ and $\mu = 6$

$P(X = 5) = \frac{e^{-6}*(6)^{5}}{(5)!} = 0.160623$

There is a 16.0623% probability that 5 messages are received in 1 hour.

(b) What is the probability that 10 messages are received in 1.5 hours?

The mean is 6 messages in one hour.

For 1.5 hours, the mean is 6*1.5 = 9 messages.

We have to find the value of P when $x = 10$ and $\mu = 9$ .

$P(X = 10) = \frac{e^{-9}*(9)^{10}}{(10)!} = 0.115880$

There is a 11.5880% probability that 10 messages are received in 1.5 hours.

(c) What is the probability that less than 2 messages are received in 1/2 hour?

The mean is 6 messages in one hour.

For 0.5 hours, the mean is 6*0.5 = 3 messages.

We have to find the value of P when $x = 2$ and $\mu = 3$ .

$P(X = 10) = \frac{e^{-3}*(3)^{2}}{(2)!} = 0.224042$

There is a 22.4042% probability that 2 messages are received in 0.5 hours.

6 0

2 years ago