Question

Draw lines to match each equation on the left to its number of solutions on the right.​

Answer 1

Answer:

1) The equation $2(4x-1)=-8x-2$ has one solution

2) The equation $2(4x-1)=8x-2$ has infinitely many solutions

3) The equation $-2(4x-1)=-8x-2$ has no solution.

Step-by-step explanation:

We need to solve the equation and match with its solution.

1) $2(4x-1)=-8x-2$

Solving and finding value of x:

$2(4x-1)=-8x-2\\8x-2=-8x-2\\8x+8x=-2+2\\16x=0\\x=0$

So, We get x =0

So, the equation $2(4x-1)=-8x-2$ has one solution

2) $2(4x-1)=8x-2$

Solving the equation and finding value of x:

$2(4x-1)=8x-2\\8x-2=8x-2\\8x-8x=-2+2\\0=0$

So, We get 0 =0

So, the equation $2(4x-1)=8x-2$ has infinitely many solutions

3) $-2(4x-1)=-8x-2$

Solving the equation and finding value of x

$-2(4x-1)=-8x-1\\-8x+2=-8x-2\\-8x+8x=-2-2\\0\neq -4$

So, we get 0 ≠ -4

So, the equation $-2(4x-1)=-8x-2$ has no solution.