Answer:
you are diluting it 8/5 times, or 1.6 times.
You could make 230*1.6 ml of 5 percent lotion.
If Melanie get's 4.10$, then Jacob get's 20.50$.
We can divide to get the unit rate:
20.50 ÷ 4.10 = 5
This means that if Jacob gets 5$, then Melanie will get 1$.
So in this case, Melanie get's 1$.
Answer:

Step-by-step explanation:
Hello!
The high school dropout rate, as a percentage of 16- through 24- year-olds who are not enrolled in school and have not earned a high school credential was is 2009 8.1%.
To thest the claim that this percentage has decreased, a polling company takes a random sample of 1000 people between the ages of 16 and 24 and finds out that 6.5% of them are highschool dropouts.
The study variable is
X: Number of individuals with age between 16 and 24 years old that are highschool dropouts.
The parameter of interest is the proportion fo highschool dropouts p
And the sample proportion is p'= 0.065
The hypotheses are:
H₀: p ≥ 0.081
H₁: p < 0.081
To study the population proportion, you have to approximate the distribution of the sampling proportion to normal applying the Central Limit Theorem, then the statistic to use is an approximate standard normal:

I hope this helps!
100 tickets were sold.
The total amount of the tickets sold is = 5 * 100 = $500.
First prize given = $100
Second prize worth = $20 * 5 = $100
Total worth of prize + $100 + $100 = $200.
Net amount of tickets sold = $500 - $200 = $300
Expected price of each ticket sold = $300/100 = 3.
Therefore, the real price of each ticket sold is $3.
Answer:
Step-by-step explanation:
The prices he was quoted are listed below: $663, $273, $410, $622, $174, $374
We would first determine the mean.
Mean = sum of terms in the data/ number of terms in the data.
Sum of terms =
663 + 273 + 410 + 622 + 174 + 374
= 2516
Number of terms = 6
Mean = 2516/6 = 419.33
Standard deviation = √summation(x - m)^2/n
summation(x - m)^2/n = (663 - 429.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2
= 179417.9334/6 = 29902.9889
Standard deviation = √29902.9889
= 172.9