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lana66690 [7]
2 years ago
8

A large school district held a district-wide track meet for all high school students. For the 2-mile run, the population of fema

le students participating follows a Normal distribution and had a mean running time of 8.8 minutes with standard deviation of 3.3 minutes. The population of male students participating also follows a Normal distribution and had a mean running time of 7.3 minutes with standard deviation 2.9 minutes. Suppose 8 female students and 8 male students who participated in the 2-mile run are selected at random from each population. Let xF represent the sample mean running time for the female students, and let xM represent the sample mean running time for the male students. a. Find and interpret the mean and standard deviation of the sampling distribution of the difference in sample means xF − xM. b. Find the probability of getting a difference in sample means xF − xM that is less than 0.
Mathematics
2 answers:
aleksklad [387]2 years ago
7 0

Answer:

B

Step-by-step explanation:

DochEvi [55]2 years ago
4 0

Answer:

If the question has

What are the mean and standard deviation of the sampling distribution of the difference in sample means x¯F−x¯M ?

It is E

Step-by-step explanation:

AP classroom uses the example with different end questions.

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Bonzo went to a carnival. At the first
Shalnov [3]

Bonzo started with 2.1 dollars

Step-by-step explanation:

Assume that Bonzo has $x

1. Change $x to cents

2. Calculate the remaining money with him after each game

3. Equate the left money in the 3rd game by zero to find x

∵ $1 = 100 cents

∴ $x = 100 x cents

First game

∵ Bonzo has 100 x cents

∵ He paid 10¢ to get in

∴ The money left is (100 x - 10)

∵ He spent half  the money he had left

- That mean the money left with him is the other have

∴ The money left with him = \frac{1}{2} (100 x - 10) = (50 x - 5) cents

∵ He spent 10¢  to get out

∴ The money left after 1st game = (50 x - 5) - 10

∴ The money left after 1st game = (50 x - 15) cents

Second game

∵ Bonzo has (50 x - 15) cents

∵ He paid 10¢ to get in

∴ The money left is (50 x - 15) - 10 = (50 x - 25)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (50 x - 25) = (25 x - 12.5) cents

∵ He spent 10¢  to get out

∴ The money left after 2nd game = (25 x - 12.5) - 10

∴ The money left after 2nd game = (25 x - 22.5) cents

Third game

∵ Bonzo has (25 x - 22.5) cents

∵ He paid 10¢ to get in

∴ The money left is (25 x - 22.5) - 10 = (25 x - 32.5)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (25 x - 32.5) = (12.5 x - 16.25) cents

∵ He spent 10¢  to get out

∴ The money left after 3rd game = (12.5 x - 16.25) - 10

∴ The money left after 3rd game = (12.5 x - 26.25) cents

∵ He found he had no money left after the 3rd game

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∴ 12.5 x - 26.25 = 0

- Add 26.25 to both sides

∴ 12.5 x = 26.25

- Divide both sides by 12.5

∴ x = 2.1

<em>Bonzo started with 2.1 dollars </em>

Learn more:

You can learn more about money in  brainly.com/question/1870710

#LearnwithBrainly

5 0
2 years ago
M2/n2 is equivalent to _____.
tankabanditka [31]

Answer:

\frac{m^2}{n^2} is equivalent to m^2 \cdot n^{-2}

Step-by-step explanation:

Using exponent rules:

a^{-n}=\frac{1}{a^n}

Given the expression:

\frac{m^2}{n^2}

⇒\frac{m^2}{n^2} = m^2 \cdot \frac{1}{n^2}

Apply the exponent rule, we have;

m^2 \cdot n^{-2}

Therefore, the given expression \frac{m^2}{n^2} is equivalent to m^2 \cdot n^{-2}

8 0
2 years ago
An ant has a mass of 0.005 gram. A grasshopper has a mass 0.5 gram..How many ants would it take to equal the mass of 1 grasshopp
lesya692 [45]

Answer:

Step-by-step explanation:

Just divide the larger mass by the smaller.

0.5 / 0.005 = 0.5 / 0.5 * 10^-2 = 1 * 10^2 = 100

It take 100 ants to equal the mass of a grasshopper.

4 0
1 year ago
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hichkok12 [17]

Answer:

2.25lbs

Step-by-step explanation:

50-47.75=2.25

5 0
2 years ago
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yaroslaw [1]
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7 0
2 years ago
Read 2 more answers
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