Ask question

Ask question

All categories

1 year ago

7

Jasmine ran for 98.4 minutes. Throughout her run, she ran at a constant pace of 8.2 minutes per mile. How many miles did Jasmine

run?\
HeLp 6Th GraDe iS haRd!!!! (actually)

1 answer:

Slav-nsk [51]1 year ago

3 0

12 miles
I dunno I legit forgot how to do it but if you divide 98.4 with 8.2 you get 12 so yuh tell me if I’m right tho

You might be interested in

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

3 years ago

Brooklyn and Nicole are both driving along the same highway in two different cars to a stadium in a distant city. At noon, Brook

3241004551 [841]

Answer: B= -54t +367

N=-50t + 347

so in total would be 5 HOURS

3 0

2 years ago

A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot

Damm [24]

Answer:

a) $p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) $\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

$p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

$\hat p$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545$

$0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591$

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.

5 0

2 years ago

"You are going to make a trash bin with a square base , vertical sides and no top. If you have 108 ft2 of material available, de

kotykmax [81]

<h2>Dimension of trash bin is 6 ft x 6 ft x 3ft .</h2>

Step-by-step explanation:

Let h be the height of box and a be the side of base square.

We have 108 ft² material.

Surface area of trash bin = 108 ft²

Surface area of trash bin = a² + 4 ah

a² + 4 ah = 108

4ah = 108 - a²

$h=\frac{108-a^2}{4a}$

Volume of trash bin, V = a²h

$V=a^2\times \frac{108-a^2}{4a}=27a-0.25a^3$

At maximum volume differentiation of volume will be zero

$dV=27da-0.25\times 3a^2da\\\\0=27da-0.75a^2da\\\\a^2=36\\\\a=6ft$

Surface area of trash bin = a² + 4 ah = 108

36 + 4 x 6 x h = 108

h = 3 ft

Dimension of trash bin is 6 ft x 6 ft x 3ft .

8 0

2 years ago

In each figure, a|| b . Determine whether the third figure is a translation image of the first figure. Write yes or no. Explain

stellarik [79]

Answer should be:

b. No; it is a reflection followed by a translation.

Hope it helps.

4 0

2 years ago

Read 2 more answers