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Orlov [11]
2 years ago
14

Brooklyn and Nicole are both driving along the same highway in two different cars to a stadium in a distant city. At noon, Brook

lyn is 367 miles away from the stadium and Nicole is 347 miles away from the stadium. Brooklyn is driving along the highway at a speed of 54 miles per hour and Nicole is driving at speed of 50 miles per hour. Let B represent Brooklyn's distance, in miles, away from the stadium t hours after noon. Let N represent Nicole's distance, in miles, away from the stadium t hours after noon. Write an equation for each situation, in terms of t, and determine the number hours after noon,t, when Brooklyn and Nicole are the same distance from the stadium.
Mathematics
1 answer:
3241004551 [841]2 years ago
3 0

Answer: B= -54t +367

N=-50t + 347

so in total would be 5 HOURS

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Use the graph of f below. Assume the entire function is graphed below.<br> Find the domain
enot [183]

ANSWER

The domain of the function is

- 3 \leqslant x \leqslant 6

or

[-3,6]

EXPLANATION

The domain of a function refers to the values of x for which the function is defined.

From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).

Therefore the function is defined for x=-3 to x=6.

Hence the domain of the function is

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[-3,6]

5 0
2 years ago
Tia Veronica Pam and Lily are sisters. Tia is eight years old and she’s two years older than Pam. Pam is five years younger than
Nastasia [14]

Answer:

Pam (6 years), Tia(8 years), Veronica(11 years) , Lily (15 years)

Step-by-step explanation:

Age of Tia = 8 years

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Given Tia is  2 years older than Pam

mathematically

age  of Pam + 2 years = age of Tia

age  of Pam + 2 years = 8 years

age  of Pam  = 8 years- 2 years = 6 years

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Given Pam is five years younger than Veronica

we can infer that age of veronica is age of Pam + 5 more years

mathematically

age  of Pam + 5 years = age of Veronica

6 years + 5 years = age of Veronica

age  of Veronica   = 11 years

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Given Veronica is four years younger than Lily

we can infer that age of Veronica is (age of Lily - 4  years)

mathematically

age of Veronica = age of lily - 4 years

11 years = age of lily - 4 years

age of lily = 11 years + 4 years = 15 years

age  of lily   = 15 years

______________________________________________

Arranging the list from youngest  to oldest we have

age  of Pam  = 6 years

Age of Tia = 8 years

age  of Veronica   = 11 years

age  of lily   = 15 years

Arranging sisters in order of youngest  to oldest

Pam, Tia, Veronica , Lily

3 0
2 years ago
NEED ASAP PLEASE HELP
sweet-ann [11.9K]

Answer:

Dilations produce similar figures because the image and pre-image will have congruent corresponding angles. The corresponding side lengths of the figures will be proportional based on the scale factor. The shape is preserved and the sides are enlarged or reduced by the scale factor

Step-by-step explanation:

6 0
1 year ago
The area of Miguel’s rectangular garden is 450 square feet. The garden is 9 feet wide.
Daniel [21]

Answer: 118 feet

Step-by-step explanation:

For a rectangular shape: Area = W × L

450 = 9 × L

450 ÷ 9

L = 50

Perimeter of a rectangular shape = 2L + 2W

Perimeter = (2 × 50) + (2 × 9)

= 100 + 18 = 118 feet

0 0
2 years ago
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
2 years ago
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