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Eduardwww [97]
2 years ago
11

Dakari makes 2 dozen jars of jam. The total weight of all of the filled jars is 211.2 ounces. When empty, each jar weighs 1.2 ou

nces. The equation can be used to calculate the weight, j, of jam in one jar. The weight of jam in one jar is ounces
Mathematics
1 answer:
Rzqust [24]2 years ago
3 0

Answer:

Step-by-step explanation:

Total weight of all of the filled jars with jam = 211.2 ounces

When empty, each jar weighs 1.2 ounces

Total weight of 2 dozens of empty jar = 24 × 1.2 ounces

= 28.8 ounces

Total weight of jam in 2 dozens jar = Total weight of all of the filled jars with jam - Total weight of 2 dozens of empty jar

= 211.2 ounces - 28.8 ounces

= 182.4 ounces

The weight of jam in one jar = 182.4 ounces / 24 jars

= 7.6 ounces

The weight of jam in one jar = 7.6 ounces

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Rina is 6x+3/8 feet tall and Ryan is 5x+1/8 feet tall. How much taller is Rina than Ryan
worty [1.4K]

Answer:

Rina is 1/4 feet taller than Ryan

Step-by-step explanation:

(height of Rina)-(height of Ryan)

6x+3/8-(5x+1/8)

6x+3/8-5x-1/8

x+3-1/8

x+2/8

x+1/4

8 0
2 years ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
there are two identical fridges for desserts. one of the fridge has 5/8 of its room left and the other fridge is only 1/8 full.
ELEN [110]

Answer:

1.5

Step-by-step explanation:

5/8 + 7/8= 1.5 or 1  1/2

6 0
2 years ago
Read 2 more answers
Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr
Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

B(5,4)→B'(4,-5)

C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

4 0
2 years ago
Read 2 more answers
Use Gauss's Law to find the charge contained in the solid hemisphere x2 + y2 + z2 ≤ a2, z ≥ 0, if the electric field is E(x, y,
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Answer:<em><u> \frac{16}{3}πa^{3} . </u></em>

Given:

x^{2}+y^{2}+z^{2} \leq a^{2}, z \geq 0

Using Gauss's Law = ∫∫s E ·dS  

= ∫∫∫ div E dV,  

⇒ Divergence (Gauss') Theorem  

= ∫∫∫ (1+1+6) dV  

= 8×(volume of the hemisphere, radius "a")  

= 8× (\frac{1}{2})(4/3)πa^{3}  

<em><u>= \frac{16}{3}πa^{3} . </u></em>

6 0
2 years ago
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