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strojnjashka [21]
1 year ago
6

4. simplify 32³/⁵. a. 2. b. 8. c. 16. d. 24​

Mathematics
1 answer:
sleet_krkn [62]1 year ago
6 0

Answer:

2^(5×3/5)=2³=8is your answer

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Estimate the quotient 57.8 ÷81
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Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).
Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).

Then

\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.

2. Find

\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).

Then

\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.

3. Find

\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).

Then

\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.

4.

\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.

3 0
2 years ago
Angelina factored (x - 4)8 and wrote that it was equal to (x2 - 42)2(x2 + 42). Use complete sentences to explain how you could c
lapo4ka [179]
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3 0
2 years ago
Let p: it is cold, q: it is humid, and r: it is snowing. Which statement represents "It is cold and humid if and only if it is s
MaRussiya [10]

Answer: The answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].


Step-by-step explanation:  Given that The statements 'p', 'q' and 'r' are defined as follows.

p : it is cold,

q : it is humid,

r : it is snowing.

The statement 'it is cold and humid if and only if it is snowing'  can be written as

(p∧q) ⇔ r.

We know that  r ⇔ s can be written as (r⇒s)∧(s⇒r).

So, (p∧q) ⇔ r can be written as [(p∧q)⇒r] ∧ [r⇒(p∧q)].

Thus, the answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].



7 0
2 years ago
Read 2 more answers
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