Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.
The rate of change of a function f(x) over an interval

is given by

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval

is given by

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval

is given by

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>

.</span>
Answer:
<u>The area of the hexagon is A. 96√3 cm²</u>
Step-by-step explanation:
Let's recall the formula of the area of an hexagon, this way:
Area = (3√3/2) * s²
Area = (3√3/2) * 8²
Area = (3√3/2) * 64
Area = 192√3/2
Area = 96√3 cm²
<u>The area of the hexagon is A. 96√3 cm²</u>
Answer:
SP = Quadrant 3 FP = Quadrant 4
Step-by-step explanation:
sp = (−5.4, 3) fp (3, −5.4) this means the line is decreasing as point y coordinate changes fro 3 to 5.4 and will be a negative slope gradient- The quadrants at top left to right are 3 and 1 and bottom left to right is 2 and 4 Labels are Quadrant 3 = R Quadrant 1 = P Quadrant 2 = Q Quadrant 4 = S The starting point is Left top side as y is positive and can only be 3 or 1 and x is negative SP = Quadrant 3 The finishing point is bottom quadrants as y is negative this time and x is positive FP = Quadrant 4 You can remember that it is often start of origin then quadrant 1 in straight line positive colorations
Error = 1/2(Maximum range - Minimum range) = 1/2(3.2-1.1) = % = 0.0105
If p is the point estimator;
Then,
Minimum range = p - Error
Maximum range = p + Error
Solving one of the two expressions,
0.011 = p - 0.0105 => p = 0.011+0.0105 = 0.0215 = 2.15%