Easy stoichiometry conversion :)
So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.
So, our first step would look like this:
10.0
------
1
Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.
So, our 2nd step would look like this:
1 mole CO2
-----------------
84.007g NaHCO3
When we put it together: our complete stoichiometry problem would look like this:
10.0g NaHCO3 1mol CO2
---------------------- x -------------------------
1 84.007g NaHCO3
Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)
And then....
Divide the top answer by the bottom answer.
10.0/84.007 is 0.119
So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.
Hope I could help!
Answer:
293.15 K.
Explanation:
It is given that, the room temperature is 20 degrees Celsius.
We need to convert this temperature into kelvin.
The conversion from degrees Celsius to Kelvin is as follows :
We have, 
So,
So, the room temperature is 293.15 kelvin.
They are considered malleable. They can be made into sheets
Happy to help! Please mark me as the brainliest!
In 1 mole of 
, there are 3 moles of ions, 1 mole of Ca^{2+} and 2 mole of 
.
Molar mass of is 110.98 g/mol. Calculating number of moles from given mass as follows:
Thus, number of moles of ions will be 
.
Since, 1 mole of any substance has 
units of that substance where is Avogadro's number.
Thus, 9.38 mol of ions will have 
number of ions.
Therefore, total number of ions in 347 g of is 
.
