Answer:
The area of new pumpkin patch is 
= 15 x² + 380 x + 2400
Step-by-step explanation:
Given as :
The length of rectangular patch = L = 40 meters
The width of rectangular patch = W = 60 meters
So, The area of rectangular patch = Length × Width
Or, 
= L × W
So , = 40 meters × 60 meters
Or, = 2400 meters²
Again The Width of new Patch = ( 40 + 3 x ) meter
And The Length of new Patch = ( 60 + 5 x ) meter
Or, = L × W
So , = ( 40 + 3 x ) meters × ( 60 + 5 x ) meters
Or, = 2400 + 200 x + 180 x + 15 x²
Or, = 15 x² + 380 x + 2400
Hence The area of new pumpkin patch is = 15 x² + 380 x + 2400 Answer
Answer:
Step-by-step explanation:
By applying <em>Pythagoras theorem</em> we can find hypotenuse of a right angle triangle.
Side of right angle triangle (a) = 5√2 cm
Side of right angle triangle (b) = 5√2 cm
Hypotenuse² = a² × b²
Answer:
<h3>
If you mean: AC=CE, the answer is: AB = 24</h3>
Step-by-step explanation:
D is the midpoint of CE, then
CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9
So: 5x + 9 = 7x - 1
-9 -9
5x = 7x - 8
-7x -7x
-2x = -8
÷(-2) ÷(-2)
x = 4
AC = CE = 10x + 18 = 40 + 18 = 58
BC = 9x - 2 = 36 - 2= 34
AB = AC - BC = 58 - 34 = 24
Answer:
18.95(0.3+0.1)
Step-by-step explanation:
Add the parenthesis and then multiply it to the cost to get the answer
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours
Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour
Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30)
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles
Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour
Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )
Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
