You're looking for a value
such that
Because the distribution is symmetric, the value of
in either case will be the same.
Now, because the distribution is continuous, you have that
The mean for the standard normal distribution is
, and because the distribution is symmetric about its mean, it follows that
.
You can consult a
score table to find the corresponding score for this probability. It turns out to be
.
------- (EF)
------ (FG)
------ + ------- =
6 + 7 =
13
A) There are 36 possible outcomes.
b) The probability of a sum of 6 is 5/36.
c) She should roll a sum of 7 45 times.
d) She should roll a sum of 10 45 times.
Explanation
a) There are 6 outcomes for the first die and 6 outcomes for the second one. By the fundamental counting principle, there are 6*6 = 36 outcomes for both dice together.
b) The ways to get a sum of 6 are:
1&5; 2&4; 3&3; 4&2; 5&1. There are 5 possibilities out of a total of 36, or 5/36.
c) The ways to get a sum of 7 are:
1&6; 2&5; 3&4; 4&3; 5&2; 6&1. There are 6 out of 36, or 6/36=1/6. Since she is rolling the dice 150 times, she should get a sum of 6
1/6(150) = 150/6 = 45 times.
d) The ways to get a sum of 10 or more are:
4&6; 5&5; 6&4; 5&6; 6&5; 6&6
There are 6 ways out of 36, or 6/36 = 1/6. Since she is rolling the dice 150 times, she should get a sum of 10 or more
1/6(150) = 150/6 = 45 times.
Answer:
idk good luck with that one :)
Step-by-step explanation:
