The dot plot or histogram will be skewed.
The mean is pulled up or down toward the tail.
The mean is affected more than the median.
Sample Response: When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.
Option 4:
is the right answer
Step-by-step explanation:
Given expression is:

In order to convert an exponent into radical form, the power should be in the form of 1/x where x is any number
so,
in case of 3/7, it will be broken down

The 1/7 will be converted into base of radical while 3 will be he exponent
![\sqrt[7]{(5x^3y^4)^3}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7B%285x%5E3y%5E4%29%5E3%7D)
Multiplying exponents
![=\sqrt[7]{5^3x^{3*3}y^{4*3}}\\=\sqrt[7]{125x^9y^{12}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B7%5D%7B5%5E3x%5E%7B3%2A3%7Dy%5E%7B4%2A3%7D%7D%5C%5C%3D%5Csqrt%5B7%5D%7B125x%5E9y%5E%7B12%7D%7D)
Hence,
Option 4:
is the right answer
Keywords: Radicals, Exponents
Learn more about exponents at:
#LearnwithBrainly
Given that the angle measure 20 and the side opposite to that angle measures 10 cm, suppose this is the height of the triangle, the hypotenuse
Such that
sin theta=opposite/hypotenuse
opposite=a=10 cm
sin 20=10/h
multiplying both sides by h we get
hsin20=10
hence;
h=10/sin20
h=29.24 cm
h=29.2 cm
For this case, the first thing we must do is define variables.
We have then:
t: number of hours
F (t): total charge
We write the function that models the problem:
Where,
b: represents an initial fee.
We must find the value of b.
For this, we use the following data:
Her total fee for a 4-hour job, for instance, is $ 32.
We have then:
From here, we clear the value of b:
Then, the function that models the problem is:
Answer:
the function's formula is:

Answer : y>0
f(x) = 9*2^x
f(x) is an exponential function

When we plug in positive value for x , the value of y is positive
When we plug in negative value for x , the value y is also positive
So for any value of x, the y value is positive always.
Range is the set of y values for which the function is defined
y values are positive , so range is y >0