The first step should be to distribue:
-4(3-5x)= -12+20x
Answer:
60º
Step-by-step explanation:
Label the radii OB and OC where AB and AC are tangents. OB and OC are 4.5 cm as they are both radii. Then we can see that OBA and OCA are both right triangles with OBA=OCA=90º. OAB=OAC=30º because the side lengths fit the criteria for a 30-60-90 triangle. OAB+OAC=60º
3x + 4y = 32....multiply by 5
5x + 5y = 50...multiply by -3
---------------
15x + 20y = 160 (result of multiplying by 5)
-15x - 15y = -150 (result of multiplying by -3)
--------------add
5y = 10
y = 10/5
y = 2
3x + 4y = 32
3x + 4(2) = 32
3x + 8 = 32
3x = 32 - 8
3x = 24
x = 24/3
x = 8
solution (8,2)
The students conclusion is incorrect......it is answer choice 1
Answer: 985 g
Step-by-step explanation:
Total mass = 8 × 500g = 4000g
Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.
4000g = X + Y + Z
let's put X and Z in terms of Y, since we're trying to solve for the second pack.
X = 2Y, and Z = Y + 60
Therefore,
4000 = X + Y + Z
4000 = 2Y + Y +Y + 60
4000 = 4Y +60
4000 - 60 = 4Y
3940 = 4Y
3940 ÷ 4 = Y
985g = Y = mass of the second pack
Answer:

Step-by-step explanation:
Represent the lure's difference with A and B;


Required
Determine the difference in depth between the lure's depth
The distance is calculated as follows;

Substitute 23 feet for A and 81 feet for B


<em>Hence, the distance between both lure's is 58 feet</em>