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Sphinxa [80]
2 years ago
12

a sample of 0.0084 mol of HCl is dissolved in water to make a 1500 mL solution. calculate the molar it’s of the HCl solution, Th

e H3O, and the pH
Chemistry
1 answer:
Allisa [31]2 years ago
7 0

Answer:

pH = 2.25

Explanation:

pH is a measurement in chemistry defined as the -log [H₃O⁺]. Molarity [], is defined as the ratio between moles of solute (HCl) and the liters of solution

To solve this question we must find the molarity of the H₃O⁺ knowing: [HCl] = [H₃O⁺]

[HCl]:

0.0084moles / 1.500L

= 0.0056M = [HCl] = [H₃O⁺]

pH = -log [H₃O⁺] = -log [0.0056M]

<h3>pH = 2.25</h3>

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2 years ago
Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl.
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The balance chemical equation is:

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Make 
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An unknown compound melting at 131 - 133 C. It is thought to be one of the following compounds: trans-cinnamic acid (133-134); b
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Answer:

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Explanation:

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trans-cinnamic            133 - 134                      110 - 120

acid

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The compound X is benzamide since the melting point range is the one closest to this compound (  130-132 ºC)

The reason there is not an exact match is not due due to the presence of impurities. The presence of impurities always lower the melting point ( it is a coligative property such as the melting point depresion of salt and water )

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5 0
2 years ago
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Afina-wow [57]

The pH of a buffer solution : 4.3

<h3>Further explanation</h3>

Given

0.2 mole HCNO

0.8 mole NaCNO

1 L solution

Required

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Solution

Acid buffer solutions consist of weak acids HCNO and their salts NaCNO.

\tt \displaystyle [H^+]=Ka\times\frac{mole\:weak\:acid}{mole\:salt\times valence}

valence according to the amount of salt anion  

Input the value :

\tt \displaystyle [H^+]=2.10^{-4}\times\frac{0.2}{0.8\times 1}\\\\(H^+]=5\times 10^{-5}\\\\pH=5-log~5\\\\pH=4.3

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