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1 year ago

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A rollercoaster car at the top of the hill, an archer preparing to release an arrow, and a lake that sits above a dam are all ex

amples of what kind of energy?
A potential energy
B kinetic energy
C gravitational energy
D consumption of energy
PLEASE NO BOTS OR SCAM

1 answer:

stepan [7]1 year ago

6 0

Answer:

potential energy

Step-by-step explanation:

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For today only I authorize you to offer a free insurance plan for one year to go to Mission signer for service dangerously in re

alukav5142 [94]

Answer:

1920

Step-by-step explanation:

7 0

1 year ago

The gestation period of rhinos (487 days) is _____ percent longer than the gestation period of bears (220 days).

Talja [164]

Answer:

The gestation period of rhinos (487 days) is 121. 3 percent longer than the gestation period of bears (220 days).

Step-by-step explanation:

Given:

Gestation period of rhinos = 487 days

Gestation period of bears = 220 days

To Find:

Percentage increase = ?

Solution:

The percentage increase = $\frac{ \text{new value} - \text{final value} }{\text{final value}} \times 100$

On substituting the values,

= $\frac{ 487 - 220}{220}\times 100$

= $\frac{267}{220}\times 100$

=> $1.213 \times 100$

=> 121.3 %

8 0

2 years ago

Which data display shows the number of observations? Check all that apply.

Leno4ka [110]

Answer: A,C,E

Step-by-step explanation:

I took the test and got it right

6 0

2 years ago

Read 2 more answers

Exercise 6.12 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they canno

tensa zangetsu [6.8K]

<h2>Answer with explanation:</h2>

As per given , we have

$\hat{p}=0.48$ , n=331

Critical value for 90% Confidence interval : $z_{\alpha/2}=1.645$

a) Confidence interval :

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$0.48\pm (1.645)\sqrt{\dfrac{0.48(1-0.48)}{331}}\\\\\approx 0.48\pm0.02746\\\\=(0.48-0.02746,\ 0.48+0.02746)\\\\=(0.45254,\ 0.50746)$

Hence, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot a ord it : $(0.45254,\ 0.50746)$

b) Margin of error : E=1.5%=0.015

Formula for sample size : $n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

For p =0.48 , we have

$n=0.48(1-0.48)(\dfrac{1.645}{0.015})^2=3001.88373333\approx3002$

Hence, the required sample size to survey = 3002

6 0

2 years ago

Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2

kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

$\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}$

Multiply -y+x=2 by 2: -2y+2x=4

$\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}$

so adding

$-2y+2x=4$

$+$

$\underline{2y-2x=7}$

$0=11$

so the system of equations becomes

$\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}$

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0

2 years ago