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NemiM [27]
1 year ago
12

Amy scheduled herself from 8am-1pm sunday through wednesday on wednesday she needed to release her intervals from 11am-1pm at th

e last minute she serviced all of the other time for which she posted what was her overall commitment adherence percentage?
Mathematics
1 answer:
OleMash [197]1 year ago
5 0

Answer:

Commitment Adherence Percentage = 81.\overline{81}%

Step-by-step explanation:

The time period Amy scheduled herself, t = 8 a.m. - 1 p.m. from Sunday through Wednesday

The period she released her interval = 11 a. m. - 1 p.m.

Commitment Adherence Percentage = Service Minutes/(Posted Minutes + Released Lockdown Minutes) × 100

Posted minutes = 5 hours/day × 60 minutes ×  4 days = 1200 minutes

Serviced minute = 5 hours/day × 60 minutes ×  3 days + 3 hours × 60 minutes/hour = 1,080 minutes

Released minutes = 2 hours × 60 minutes/hour = 120 minutes

Commitment Adherence Percentage = (1,080/(1,200 + 120)) × 100 = 81.\overline{81}%

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RS=2x-8, ST= 11, RT= x+10
swat32

Answer:

X=7 ST=11 RT=17

Step-by-step explanation:

RT=RS+ST. RS= 2(7)-8. ST=11

X+10=2x-8+11. =14-8=6. RT= x+10

X+10=2x+3. RS=6. 7+10=17

10=x+3. RT=17

X=7

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