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otez555 [7]
2 years ago
12

A golfer and her caddy see lightning nearby. the golfer is about to take his shot with a metal club, while her caddy is holding

a plastic handled umbrella. which person is at greater risk? Explain why?
Engineering
1 answer:
Sveta_85 [38]2 years ago
7 0

Answer:

The golfer is at greater risk.

Explanation:

The golfer is holding a metal club. Metal is a good conductor for electricity (lightning), meaning electrons can pass through easily. Her caddy is at lesser risk because she is holding a plastic handled umbrella. Plastic is an insulator, which does not easily allow the movement of electrons to pass.

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A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as hea
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Answer:

im not sure

Explanation:

8 0
2 years ago
A curve in a speed track has a radius of 1000 ft and a rated speed of 120 mi/h. (From Sample Prob. 12.7 is the definition of rat
forsale [732]

Answer:

tan \theta = \frac{(176ft/s)^2}{1000 ft 32.2 ft/s^2}= 0.962

\theta = tan^{-1} (0.962) = 43.89

Explanation:

If the question is: Determine the banking angle θ

We have the forces involved on the figure attached.

For this case we know that the weight is given by:

W = mg

And for this case the centripetal acceleration would be given by:

a=\frac{v^2}{r}

If we analyze the sum of forces on x and y we have:

\sum F_x = m a_x

F + W sin \theta = ma cos theta

And if we solve for the force we got:

F = ma cos \theta - mg sin \theta = \frac{mv^2}{r} cos \theta - mg sin \theta

\sum F_y = m a_y

N - W cos \theta = ma sin \theta

If we solve for the normal force we got:

N =W cos \theta + ma sin \theta = \frac{mv^2}{r} sin \theta + mg cos \theta

In order to find the banking angle we use the fact that F =0

0 = \frac{mv^2}{r} cos \theta - mg sin \theta

tan \theta= \frac{v^2}{rg}

The velocity on this case is 120 mi/h if we convert this into ft/ s we got:

120 mi/h * \frac{5280 ft}{1mi} *\frac{1hr}{3600 s}= 176 ft/s

And then we have this:

tan \theta = \frac{(176ft/s)^2}{1000 ft 32.2 ft/s^2}= 0.962

\theta = tan^{-1} (0.962) = 43.89

5 0
2 years ago
The electrical energy used by an air conditioner for 2 minutes is 180 kJ. Calculate the power of this air conditioner in the fol
ELEN [110]

Answer:

I hope it is correct.....

5 0
2 years ago
The ingredient weights for making 1 yd (cyd) of concrete by assuming aggregates in SSD state are given below. The volume of air
Pachacha [2.7K]

Answer:

Explanation:

Ans) Given batch weight of each component :

Cement = 700 lb

Water = 315 lb

Coarse aggregate = 1575 lb

Fine aggregate = 1100 lb

Part 1) Amount of water = 328.5 lb

Amount of water is needed to be increased if the aggregates has absorption capacity, To maintain constant water cement ratio, the mixing water is increased because some of the water is absorbed by aggregates.

Amount of water absorbed = 328.5 lb - 315 lb = 13.5 lb

Total amount of aggregates = 1575 + 1100 = 2675 lb

=> % Absorption capacity = 13.5 x 100 / 2675 = 0.5 %

Hence, new amount of Coarse aggregate = (1 - 0.005) x 1575 lb = 1567.125 lb

New amount of fine aggregate = (1 - 0.005) x 1100 = 1094.5 lb

Since, water cement ratio is maintained constant , amount of cement remains unchanged

=> Volume of water = 328.5 / 62.4 = 5.26 ft3

=> Volume of cement = 700 / (3.15 x 62.4) = 3.56 ft3

=> Volume of coarse aggregate = 1567.125 / (2.4 x 62.4) = 10.46 ft3

=> Volume of fine aggregate = 1100 / (2.4 x 62.4) = 7.34 ft3

Volume of air = 2% = 0.02 x 27 = 0.54 ft3

Total concrete volume = 5.26 + 3.56 + 10.46 + 7.34 + 0.54 \approx 27 ft3 = 1 yd3

Hence, calculated amount of each component is correct

Part 2) We know, minus sign indicated that the aggregate will absorb some moisture from concrete, hence mixing water amount needed to be corrected .

=> Amount of water absorbed by coarse aggregate = 0.01 x 1567.125 lb = 15.67 lb

=> Amount of water absorbed by fine aggregate = 0.02 x 1094.50 lb = 21.89 lb

Total amount of water absorbed = 15.67 + 21.89 = 37.56 lb

To maintain same water cement ratio, amount of mixing water is needed to be increased

=> Corrected amount of mixing water = 328.5 lb + 37.56 lb = 366 lb

=> Corrected amount of coarse aggregate = (1 - 0.01) x 1567.125 = 1551.45 lb

=> Corrected amount of fine aggregate = (1 - 0.02) x 1094.5 = 1072.6 lb

Part 3) We know,

Unit weight = Sum of weight of each material / Total volume

=> Sum of weight = 366 + 700 + 1551.45 + 1072.6 = 3690.05 lb

Total volume = 1 yd3 or 27 ft3

=> Expected Unit Weight = 3690.05 lb / 27 ft3 = 136.67 lb/ft3

Also, Concrete Yield = Weight of all components / Unit weight of concrete

=> Yield = 3690.05 / 136.67 = 27 ft3 or 1 yd3

4 0
2 years ago
At an impaired driver checkpoint, the time required to conduct the impairment test varies (according to an exponential distribut
professor190 [17]

Answer:

Option (d) 2 min/veh

Explanation:

Data provided in the question:

Average time required = 60 seconds

Therefore,

The maximum capacity that can be accommodated on the system, μ = 60 veh/hr

Average Arrival rate, λ = 30 vehicles per hour

Now,

The average time spent by the vehicle is given as

⇒ \frac{1}{\mu(1-\frac{\lambda}{\mu})}

thus,

on substituting the respective values, we get

Average time spent by the vehicle = \frac{1}{60(1-\frac{30}{60})}

or

Average time spent by the vehicle = \frac{1}{60(1-0.5)}

or

Average time spent by the vehicle = \frac{1}{60(0.5)}

or

Average time spent by the vehicle = \frac{1}{30} hr/veh

or

Average time spent by the vehicle = \frac{1}{30}\times60 min/veh

[ 1 hour = 60 minutes]

thus,

Average time spent by the vehicle = 2 min/veh

Hence,

Option (d) 2 min/veh

7 0
2 years ago
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