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julsineya [31]
2 years ago
5

Which of these parts serves as the front end cross structure on most vehicles?

Engineering
2 answers:
Murljashka [212]2 years ago
8 0

Answer:

Rear body panel. Rear bumper cover. Rear rails.

Explanation:

Salsk061 [2.6K]2 years ago
7 0
Rear body panel. Rear bumper cover. Rear rails. have a good day
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If a server takes precisely 15 seconds to serve a customer and customers arrive exactly every 20 seconds, what is the average wa
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The average waiting time is 10 seconds
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A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 3.5 mm (0.14 in
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To resolve this problem we have,

R=3.5mm\\F_f1=950N\\L_1=50mm\\b=12mm\\L_2=40mm

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\sigma{fs}=\frac{F_{f1}L}{\pi R^3}\\\sigma{fs}=\frac{(950)(50*10^{-3})}{\pi 3.5*10^{-3}}\\\sigma{fs}=352.65Mpa

After that, we can calculate the flexural strenght for the square cross section using the previously value.

\sigma{fs}=\frac{F_{f2}L}{\pi R^3}\\(352.65*10^6)=\frac{3Ff(40*10^{-3})}{2(12*10^{-10})}\\F_{f2}=\frac{352.65*10^6}{34722.22}\\F_{f2}=10156.32N\\F_{f2}=10.2kN

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The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm
Angelina_Jolie [31]

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

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= \frac{38}{0.25}

= 152 \ layers

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= 1.25 mm

Velocity (v):

= 40 mm/s

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The area of one layer will be:

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= \frac{1444}{50}

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The time required for one layer will be:

= 15 \ sec

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= 15+28.88

= 43.88 \ sec

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Number of layers = 152

Therefore,

Total time will be:

= 152\times 43.88

= 6669.76 \ sec

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