An elephant has a mass of 6.8 × 10 3 kg.

Photon Lighting Company determines that the supply and demand functions for its most popular lamp are as follows: S(p) = 400 - 4

BlackZzzverrR [31]

S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3

S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24

6 0

2 years ago

1. Melissa went to lunch with two friends. She purchased 3 corn dogs, 2 fruit cups, and

umka2103 [35]

Answer:

14 is the answer.

Step-by-step explanation:

8 0

2 years ago

What is the product and simplest form 2/3 times 1/8

ludmilkaskok [199]

Answer:

$\frac{1}{12}$

Step-by-step explanation:

Since we're finding the product, we have to multiply:

$\frac{2}{3}$ × $\frac{1}{8}$

You can simplify in this stage by using the "butterfly method", and dividing $2$ by $2$ , and $8$ by $2$ , you'd then have:

$\frac{1}{3}$ × $\frac{1}{4}$

Multiply the numerators and the denominators to get:

$\frac{1}{12}$

~

If you prefer the longer way, again, multiply:

$\frac{2}{3}$ × $\frac{1}{8}$

Multiply the numerators and the denominators:

$\frac{2}{24}$

Simplify the fraction by dividing both the numerator and denominator by $2$ :

$\frac{1}{12}$

7 0

2 years ago

Read 2 more answers

At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25

denpristay [2]

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

Step-by-step explanation:

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 < X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is $0.9544(100) = 95.44$ % .

3 0

2 years ago

Please help me. The original blueprint of the Moreno’s’ living room has a scale of 2 inches= 5 feet. The family wants to use a n

Svetradugi [14.3K]

Answer:

Part a) The scale of the new blueprint is $\frac{5}{8} \frac{in}{ft}$

Part b) The width of the living room in the new blueprint is $9.4\ in$

Step-by-step explanation:

we know that

The scale of the original blueprint is

$\frac{2}{5}\frac{in}{ft}$

and

the width of the living room on the original blueprint is 6 inches

so

Find the actual width of the living room, using proportion

$\frac{2}{5}\frac{in}{ft}=\frac{6}{x}\frac{in}{ft}\\ \\x=5*6/2\\ \\x=15\ ft$

Find the actual length of the living room, using proportion

$\frac{2}{5}\frac{in}{ft}=\frac{9.6}{x}\frac{in}{ft}\\ \\x=5*9.6/2\\ \\x=24\ ft$

Find the scale of the new blueprint, divide the length of the living room on the new blueprint by the actual length of the living room

$\frac{15}{24} \frac{in}{ft}$

simplify

$\frac{5}{8} \frac{in}{ft}$

Find the width of the living room in the new blueprint, using proportion

$\frac{5}{8}\frac{in}{ft}=\frac{x}{15}\frac{in}{ft}\\ \\x=15*5/8\\ \\x=9.4\ in$

3 0

2 years ago