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kotegsom [21]
1 year ago
15

Sally's parents deposited $15,000 into a college savings account on her third birthday. The account had an interest rate of 9.6%

compounded annually. They were hoping that the money would double twice by the time she was 18 years old. Using the rule of 72, t = StartFraction 72 Over r EndFraction will their hopes come true?
Mathematics
1 answer:
77julia77 [94]1 year ago
6 0

Answer:

their hopes will come true

Step-by-step explanation:

Using the formula for calculating amount expressed as;

A = P(1+r)^t

Given

P = $15000

r = 9.6% = 0.096

t = 15years (18-3)

Substitute;

A = 15,000(1+0.096)^15

A = 15,000(1.096)^15

A = 15000(3.9551)

A = 59,326.6

As we can see, the money is even more than twice the original amount, this shows that their hopes will come true

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Alex787 [66]

Answer:

c

Step-by-step explanation:

since the axis of symmetry is 0, and the y intercept is 2, the answer should be c

4 0
2 years ago
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Using the power series methods solve the 1st order Lane-Emden Equation:
nikklg [1K]

Answer:

Step-by-step explanation:

xy = 2y + xy = 0

Hence, 2y + xy = 0 ---------(1)

Differentiating equation (1) n times by Leibnitz theorem, gives:

2y(n) + xy(n) + ny(n - 1) = 0

Let x = 0: 2y(n) + ny(n - 1) = 0

2y(n) = -ny(n - 1)

∴ y(n) = -ny(n - 1)/2 for n ≥ 1

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For n = 3: -3y(2)/2

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2 years ago
-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz
vitfil [10]
To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
minus 1 from both sides and minus 6(3^x) from both sides
0=3^{2x}-16(3^x)-1
use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
for ax^2+bx+c=0 x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

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WILL GIVE BRAINLIEST ANSWER!!
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Check the picture below.

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make sure your calculator is in Degree mode.

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