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Vitek1552 [10]
1 year ago
4

By the definition of a ▱, AD∥BC and AB∥DC. Using, AD as a transversal, ∠A and ∠ are same-side interior angles, so they are . Usi

ng side as a transversal, ∠B and ∠C are same-side interior angles, so they are supplementary. Using AB as a transversal, ∠A and ∠B are same-side interior angles, so they are supplementary. Therefore, ∠A is congruent to ∠C because they are supplements of the same angle. Similarly, ∠B is congruent to ∠.
Mathematics
2 answers:
barxatty [35]1 year ago
5 0

Step-by-step explanation:

is it a question ? please check.

ivolga24 [154]1 year ago
3 0

Answer:

Step-by-step explanation:

D.

supplementary.

BC.

D.

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Which of the statements below is true concerning bar​ graphs? Choose the correct answer below.
nordsb [41]

Answer:

C. The height of each bar represents the category's frequency or relative frequency

Step-by-step explanation:

8 0
2 years ago
Each quart of paint costs $8 and covers 90 square feet. Find the total cost to paint this wall once. Justify your answer
Galina-37 [17]

Answer:

$16

Step-by-step explanation:

4 0
2 years ago
Without properly working spark plugs, a vehicle will not run. For a specific vehicle, the spark plugs are supposed to have a gap
Salsk061 [2.6K]

Answer:

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the mean of the Normal distribution = 4.1mm</em>

<em>Given that the standard deviation of the Normal distribution = 0.0075mm</em>

<em>Let 'X' be the random variable in a normal distribution</em>

Given that X₁ = 3.9mm

Z_{1} = \frac{X_{1} -mean}{S.D}

Z_{1} = \frac{3.9 -4.1}{0.075} =  -2.666

Given that X₂ = 4.3mm

Z_{2} = \frac{X_{2} -mean}{S.D}

Z_{1} = \frac{4.3 -4.1}{0.075} =  2.666

<u><em>Step(ii):-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3) = P(-2.666≤Z≤2.666)</em>

<em>                      = P(Z≤2.666)-P(Z≤-2.666)</em>

<em>                     = 0.5 +A(2.666) - (0.5-A(2.666)</em>

<em>                    = 2 × A(2.666)</em>

<em>                  = 2×0.4961</em>

<em>                  = 0.9922</em>

<u><em>Final answer:-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

<em></em>

3 0
1 year ago
If f (x) = StartRoot 4 x + 9 EndRoot + 2, which inequality can be used to find the domain of f(x)? StartRoot 4 x EndRoot greater
maxonik [38]

Answer:

Step-by-step explanation:

"f (x) = StartRoot 4 x + 9 EndRoot + 2" should be written as

 

Note that √(4x + 9) is a variation of the basic function y = √x, whose domain is [0, ∞ ).

The domain of f(x) = √(4x + 9) + 2 is found by taking the "argument" 4x + 9 of √(4x + 9) and setting it equal to zero:

4x + 9 ≥ 0, or

4x ≥ -9, or

x ≥ -9/4

This is the domain of the given function f(x) = √(4x + 9) + 2.  So long as x is ≥ -9/4, the function f(x) will be defined.

6 0
2 years ago
Read 2 more answers
According to the scatterplot below, which statement is correct?
FinnZ [79.3K]

Answer:

Hey there

Step-by-step explanation:

The input, or independent variable, is years in operation.

Step-by-step explanation:

In an ordered pair (x, y),  the independent variable or input is x  and y is the dependent variable or the output.

Therefore, the values on x-axis determine the results or output on y-axis.

The ordered pairs (x, y) are:

(1, 11)     ⇒  there are 11 enrollees on Year 1

(2, 33)   ⇒  there are 33 enrollees on Year 2

(3, 39)   ⇒  there are 39 enrollees on Year 3

(4, 58)   ⇒  there are 58 enrollees on Year 4

(5, 85)   ⇒  there are 85 enrollees on Year 5

Where:

x are values on the x-axis that refers to number of years in operation

y are values on the y-axis that refers to the corresponding numbers of enrollees for each year.

Even without the graph, the correct statements i:

The input, or independent variable, is years in operation.

- brainly user

8 0
1 year ago
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