Ask question

Ask question

All categories

2 years ago

9

According to the rule of 72, if Randall invests $700 and $1900 into two separate accounts with the same interest rate, which amo

unt will double faster? A. Both will double at the same rate. B. $1900 C. $700 D. None of the above

2 answers:

soldi70 [24.7K]2 years ago

8 0

The answer is A.) Both will double at the same rate. Now I am going to explain how I know. If the interest rate of each is 1% this means that 1% of each will be added to the accounts per month. $1900 x 1% is $19 per month. $700 x 1% is $7 per month. Now I will divide 1900 by 19 to find how many months it will take to double the money in that account. It will take 100 months for the account with $1900 in it to double. Now I will multiply $700 by $7 to get 100 months also. This means that each account will take 100 months to double so your answer is A.) Both will double at the same rate.

Elanso [62]2 years ago

6 0

Answer:

both will double at the same rate

Step-by-step explanation:

apex

You might be interested in

Jasmine wants to use her savings of $1128 to buy video games and music CDs. The total price of the music CDs she bought was $72.

vredina [299]

The most she can buy would be 24.
1128 - 72 = 1056
43 * 24 = 1034
43* 25 = 1075
hope this helped

8 0

2 years ago

Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

$k (t) = c * t$

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

Substituting values:

$2 = c * 18$

Clearing c we have:

$c = \frac{2}{18}$

$c = \frac{1}{9}$

Then, the equation is given by:

$k (t) = \frac{1}{9} * t$

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

$k (t) = \frac{1}{9} * t$

7 0

2 years ago

Read 2 more answers

One serving of pretzels contains 1.5 grams of fat. That is 3% of the daily amount recommended for a 2,000 calorie diet. How many

OleMash [197]

Step-by-step explanation:

given that 1.5 gram of fat =3% of 2000 calorie diet.

Thus, 1.5 gram of fat contributes to 3/100*2000= 60 calorie of diet.

Generally 6% of the diet must be fat.(recommended)

Since, 1.5 gram = 3%

thus, 3 gram =6%.

8 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

7nadin3 [17]

The equation of the cone should be $z=\sqrt{x^2+y^2}$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u\,\vec k$

with $1\le u\le2$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k$

Then the integral of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_1^2(-u\cos v\,\vec\imath-u\sin v\,\vec\jmath+u^3\,\vec k)\cdot(u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_1^2(-u^2-u^4)\,\mathrm du\,\mathrm dv$

$=\displaystyle-2\pi\int_1^2(u^2+u^4)\,\mathrm du\,\mathrm dv=\boxed{-\frac{256\pi}{15}}$

3 0

2 years ago

Read 2 more answers

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean = $\overline{x}=\text{48.47 pounds}$

Standard deviation : $\sigma=\text{ 3.1 pounds.}$

Sample size : n = 36

Claim : $\mu\neq50$

∴ $H_0:\mu=50$

$H_1:\mu\neq50$

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject $H_0$ if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96$

We reject $H_0$ since $-2.96\leq -1.96$ . We have statistically significant evidence at $\alpha=0.05$ to show that the mean amount of garbage per bin is not different from 50.

5 0

2 years ago