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dolphi86 [110]
2 years ago
7

Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a

verage speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, then Riko will be behind Yuto when 0 ≤ t < 52.5, where t is time in minutes. Explain what this solution means and why t cannot be less than zero
Mathematics
2 answers:
katovenus [111]2 years ago
8 0

Answer:

Step-by-step explanation:

the statement  0 < t < 52.5  represents all the time values for when Riko is behind Yuto,   she catches up to Yuto at 52.5 minutes into her ride.   Her ride starts at time of zero , so she can't have a negative time,  like -4  because she isn't involved in the activity of riding her bike.  

Triss [41]2 years ago
3 0

Answer:

The solution means that Riko will be behind Yuto from the time she leaves the house, which corresponds to t = 0, until the time she catches up to Yuko after 52.5 minutes, which corresponds to t = 52.5. The reason that t cannot be less than zero is because it represents time, and time cannot be negative.

Step-by-step explanation:

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Helen’s house is located on a rectangular lot that is 1 1/8 miles by 9/10 mile.Estimate the distance around the lot
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Answer:

The distance around the lot is 4.05 miles .

Step-by-step explanation:

Formula

Perimeter\ of\ rectangle = 2 (Length + Breadth)

As given

Helen’s\ house\ is\ located\ on\ a\ rectangular\ lot\ that\ is\ 1 \frac{1}{8}\ miles\ by\ \frac{9}{10}\ mile.

i.e

Helen’s\ house\ is\ located\ on\ a\ rectangular\ lot\ that\ is\ \frac{9}{8}\ miles\ by\ \frac{9}{10}\ mile.

Here

Length = \frac{9}{8}\ miles

Breadth = \frac{9}{10}\ miles

Put in the formula

Perimeter\ of\ rectangle = 2(\frac{9}{8}+\frac{9}{10})

L.C.M of (8,10) = 40

Perimeter\ of\ rectangle = \frac{2\times (9\times 5+9\times 4)}{40}

Perimeter\ of\ rectangle = \frac{2\times (45+36)}{40}

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Perimeter of rectangle = 4.05 miles

Therefore the  distance around the lot is 4.05 miles .


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2 years ago
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Which expression can be used to find 20 percent of 92? One-fifth times 92 StartFraction 1 Over 20 EndFraction times 92 One-half
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Answer:

The answer to your question is (\frac{1}{5}) 9

Step-by-step explanation:

To solve this problem we must use proportions

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Use cross multiplication to solve this proportion

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Simplify \frac{20}{100}

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AURORKA [14]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷Yes.

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➶ Good Luck (:

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